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Sets

This topic has 2 member replies
rajs.kumar Senior | Next Rank: 100 Posts Default Avatar
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Sets

Post Thu Oct 26, 2006 2:35 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    One night a certain motel rented 3/4 of its rooms, including 2/3 of its air-conditioned rooms. If 3/5 of its rooms were air-conditioned, what percent of the rooms that were not rented were air-conditioned.

    A. 20%
    B. 331/3%
    C. 35%
    D. 40%
    E. 80%

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    ajith Legendary Member
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    Post Thu Oct 26, 2006 2:59 am
    ((1-2/3)*3/5)/(1-3/4)

    =(1/5)/(1/4)=(4/5)=80%

    So I go for E

    countingdolls Junior | Next Rank: 30 Posts Default Avatar
    Joined
    02 Oct 2006
    Posted:
    13 messages
    Post Thu Oct 26, 2006 7:31 am
    80% it is.

    In case you find it difficult to use the fractions, assume the total no of rooms to be a value, say 100........problem becomes easier

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