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mukherjee.tanuj3@gmail.co Really wants to Beat The GMAT!
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red ball_prep Post Mon Apr 28, 2014 8:36 pm
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    perwinsharma Just gettin' started!
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    Post Sat Jul 26, 2014 11:50 pm
    Here we know, that all the variables B, R, and W are positive.

    1) R/(B + W) > W/(B + R)
    If we cross multiply
    RB + R^2 > WB + W^2
    => (R^2 - W^2) + (RB - WB) > 0
    => (R + W) (R - W) + B(R - W) > 0
    => (R- W) (B + R + W) > 0
    => We know that B + R + W > 0 as all the variables are positive
    => R - W has to be more than zero
    => R > W
    SUFFICIENT

    2) B - W > R
    Doesn't give us any information.

    The answer is (A).


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    Post Sun Jul 27, 2014 2:32 am
    Quote:
    A certain jar contains only b black marbles, w white marbles and r red marbles. If one marble is to be chosen at random from the jar, is the probability that the marble chosen will be red greater then the probability that the marble chosen will be white?

    (1) r/(b+w) > w/(b+r)
    (2) b-w > r
    Very little math is needed here.
    Just use common sense.

    Question stem, rephrased: Is R>W?

    Statement 1: r/(b+w) > w/(b+r)
    Put into words:
    The ratio of R to the OTHER marbles is greater than the ratio of W to the OTHER marbles.
    The statement above can be true only if THERE ARE MORE RED MARBLES THAN WHITE MARBLES.
    Thus, R>W.
    SUFFICIENT.

    Statement 2: b-w > r
    B > R+W.
    No way to determine whether R>W.
    INSUFFICIENT.

    The correct answer is A.

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    Last edited by GMATGuruNY on Sun Jul 27, 2014 3:24 am; edited 1 time in total

    Thanked by: binit
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    Post Sun Jul 27, 2014 2:45 am
    Another way to evaluate statement 1.

    Statement 1: r/(b+w) > w/(b+r)
    Test whether it's possible that R=W or that R<W.

    Case 1: R=W=1
    Substituting R=1 and W=1 into r/(b+w) > w/(b+r), we get:
    1/(b+1) > 1/(b+1)
    b+1 > b+1
    0 > 0.
    Doesn't work.
    Case 1 illustrates that R=W is not viable.

    Case 2: R=1 and W=2
    Substituting R=1 and W=2 into r/(b+w) > w/(b+r), we get:
    1/(b+2) > 2/(b+1)
    b+1 > 2b + 4
    -b > 3
    b < -3.
    Not possible: b must be a positive value.
    Case 2 illustrates that R<W is not viable.

    Since it's not possible that R=W or that R<W, it must be true that R>W.
    SUFFICIENT.

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    Post Sun Jul 27, 2014 9:57 am
    Quote:
    A certain jar contains only b black marbles, w white marbles and r red marbles. If one marble is to be chosen at random from the jar, is the probability that the marble chosen will be red greater then the probability that the marble chosen will be white?

    (1) r/(b+w) > w/(b+r)
    (2) b-w > r
    Probability of Red marble picked = r/(b+w+r)
    Probability of White marble picked = w/(b+w+r)

    Question : Is r/(b+w+r) > w/(b+w+r)

    Question Rephrased : Is r > w ?

    Statement 1) r/(b+w) > w/(b+r)
    i.e. r(b+r) > w(b+w)
    i.e. rb + r^2 > wb + w^2
    i.e. rb - wb > w^2 - r^2
    i.e. b(r - w) > (w - r)(w + r)
    i.e. 0 > (w - r)(w + r) - b(r - w)
    i.e. 0 > (w - r)(w + r) + b(w - r)
    i.e. 0 > (w - r)(w + r + b)
    BUT (w + r + b) is definitely Greater than Zero
    Therefore, (w-r) is certainly Negative
    i.e. w-r < 0
    i.e. w < r
    SUFFICIENT

    Statement 2) b-w > r
    Due to b being present in the above expression, w and r can't be compared, therefore
    INSUFFICIENT

    Answer: Option A

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    Post Sun Jul 27, 2014 10:59 am
    Quote:
    A certain jar contains only b black marbles, w white marbles and r red marbles. If one marble is to be chosen at random from the jar, is the probability that the marble chosen will be red greater than the probability that the marble chosen will be white?

    (1) r/(b + w) > w/(b + r)
    (2) b - w > r
    Target question: Is the probability that the marble chosen will be red greater than the probability that the marble chosen will be white?

    We can rephrase the target question as...
    REPHRASED target question: Is r > w?

    Statement 1: r/(b + w) > w/(b + r)
    Let's let T = the TOTAL number of marbles in the jar.
    This means that b + w + r = T
    This also means that b + w = T - r
    And it means that b + r = T - w
    So, we can take statement 1, r/(b + w) > w/(b + r), and rewrite it as...
    r/(T - r) > w/(T - w)
    Multiply both sides by (T - r) to get: r > w(T - r)/(T - w)
    Multiply both sides by (T - w) to get: r(T - w) > w(T - r)
    Expand both sides: rT - rw > wT - rw
    Add rw to both sides: rT > wT
    Divide both sides by T to get: r > w
    Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT

    Statement 2: b - w > r
    Add w to both sides to get: b > w + r
    All this means is that there are more black marbles than there are white and red marbles combined.
    Given this information, there's no way to determine whether or not r is greater than w
    Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

    Answer = A

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    Brent

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    binit Really wants to Beat The GMAT! Default Avatar
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    Post Sun May 03, 2015 3:47 am
    St 1: r/(b+w)> w/(b+r) add 1 to both sides and simplify
    So, (r+b+w)/(b+w) > (w+b+r)/(b+r) both the numerators are equal now
    or, 1/b+w > 1/b+r
    or, b+w < b+r ,inequality will be reversed
    or w < r. Sufficient.

    St 2: b > w+r no idea about w and r, insufficient.

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    Matt@VeritasPrep GMAT Instructor
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    Post Sun May 03, 2015 11:52 pm
    binit wrote:
    or, 1/b+w > 1/b+r
    or, b+w < b+r ,inequality will be reversed
    Be careful, this is misleading. Since b, w, and r are all positive, you're just multiplying both sides by (b+w)(b+r) and arriving at b + r > b + w. This isn't a reversal, just a rearrangement. ((b + w) need not always be on the left hand side.)

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    binit Really wants to Beat The GMAT! Default Avatar
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    Post Mon May 04, 2015 10:43 pm
    Quote:
    Since b, w, and r are all positive, you're just multiplying both sides by (b+w)(b+r) and arriving at b + r > b + w. This isn't a reversal, just a rearrangement.
    Thanks Matt, for pointing that out. Yeah, "reversal" is not the right term here. I am poor at vocab Wink What I had in mind was: since, 1/3 > 1/5, we can readily simplify it as: 3 < 5.

    ~Binit.

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