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## Ratio problem

pavan555 Just gettin' started!
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Ratio problem Tue Apr 24, 2012 8:58 am
Elapsed Time: 00:00
• Lap #[LAPCOUNT] ([LAPTIME])

Tom, Dick and Harry went for lunch to a restaurant. Tom had \$100 with him, Dick had \$60 and Harry had \$40. They got a bill for \$104 and decided to give a tip of \$16. They further decided to share the total expenses in the ratio of the amounts of money each carried. The amount of money which Tom paid more than what Harry paid is
A. 120
B. 200
C. 60
D. 24
E. 36

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aneesh.kg GMAT Destroyer!
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Tue Apr 24, 2012 10:12 am
Tom : Dick : Harry : Total = 100 : 60 : 40 : 200 = T : D : H : 120
100 : 200 = T : 120, or T = 60
40 : 200 = H : 120, or H = 24
T - H = 60 - 24 = 36

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Tue Apr 24, 2012 4:07 pm
pavan555 wrote:

Tom, Dick and Harry went for lunch to a restaurant. Tom had \$100 with him, Dick had \$60 and Harry had \$40. They got a bill for \$104 and decided to give a tip of \$16. They further decided to share the total expenses in the ratio of the amounts of money each carried. The amount of money which Tom paid more than what Harry paid is
A. 120
B. 200
C. 60
D. 24
E. 36
T : D : H = 100:60:40 = 10:6:4 = 5:3:2.
The sum of the values in the ratio = 5+3+2 = 10.
The total amount paid = 104+16 = 120.
Since the total amount paid is 12 times the sum of the values in the ratio, all of the values in the ratio must be multiplied by a factor of 12:
T : D : H = 12(5:3:2) = 60:36:24.
Thus, T-H = 60-24 = 36.

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