Welcome! Check out our free B-School Guides to learn how you compare with other applicants.
Login or Register

Rates and Distance

This topic has 2 expert replies and 0 member replies
singhmaharaj Rising GMAT Star
Joined
10 Feb 2009
Posted:
38 messages
Followed by:
2 members
Target GMAT Score:
700
Rates and Distance Post Tue May 06, 2014 5:17 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 20 miles per hour. The cyclist stops to wait for the hiker 5 minutes after passing her, while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up?


    A) 6 2/3

    B) 15

    C) 20

    D) 25

    E) 26 2/3

    Need free GMAT or MBA advice from an expert? Register for Beat The GMAT now and post your question in these forums!
    Post Tue May 06, 2014 5:20 am
    singhmaharaj wrote:
    A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 20 miles per hour. The cyclist stops to wait for the hiker 5 minutes after passing her, while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up?


    A) 6 2/3

    B) 15

    C) 20

    D) 25

    E) 26 2/3
    Here's one approach:

    5 minutes after the cyclist passes the hiker
    The cyclist is traveling 16 mile per hour faster than the hiker.
    Distance = (time)(speed)
    Time = 5 minutes = 1/12 hours
    So, the distance between them = (16)(1/12) = 16/12 = 4/3 miles

    Time for hiker to catch up
    Distance = 4/3 miles
    Hiker's speed = 4 miles per hour
    Time = distance/time = (4/3)/4 = 1/3 hours = 20 minutes = C

    Cheers,
    Brent

    _________________
    Brent Hanneson – Founder of GMATPrepNow.com
    Use our video course along with Beat The GMAT's free 60-Day Study Guide

    Enter our contest to win a free course.

    Thanked by: Phuonganh Ta, Harsh@rayal
    GMAT Prep Now's comprehensive video course can be used in conjunction with Beat The GMAT’s FREE 60-Day Study Guide and reach your target score in 2 months!
    Post Tue May 06, 2014 5:28 am
    Quote:
    A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist traveling in the same direction along the same path at a constant rate of 20 miles per hour. The cyclist stops to wait for the hiker 5 minutes after passing her, while the hiker continue to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up?

    1.6 2/3
    2.15
    3.20
    4.25
    5.26 2/3
    Rate and time are RECIPROCALS.
    The RATE RATIO = hiker : cyclist = 4:20 = 1:5.
    Thus, the TIME RATIO = hiker : cyclist = 5:1.
    The implication is that the hiker will take 5 TIMES AS LONG as the cyclist to travel the same distance.
    Thus, when the cyclist passes the hiker, the hiker will then require 25 minutes to travel the number of miles traveled by the cyclist in 5 minutes.
    Time difference = hiker's time - cyclist's time = 25-5 = 20 minutes.
    Thus, the cyclist will have to wait 20 minutes for the hiker to catch up.

    The correct answer is C.

    _________________
    Mitch Hunt
    GMAT Private Tutor
    GMATGuruNY@gmail.com
    If you find one of my posts helpful, please take a moment to click on the "Thank" icon.
    Available for tutoring in NYC and long-distance.
    For more information, please email me at GMATGuruNY@gmail.com.

    Thanked by: Harsh@rayal
    Free GMAT Practice Test How can you improve your test score if you don't know your baseline score? Take a free online practice exam. Get started on achieving your dream score today! Sign up now.

    Best Conversation Starters

    1 ziyuenlau 49 topics
    2 Mo2men 27 topics
    3 NandishSS 7 topics
    4 rsarashi 6 topics
    5 divsragha 5 topics
    See More Top Beat The GMAT Members...

    Most Active Experts

    1 image description GMATGuruNY

    The Princeton Review Teacher

    99 posts
    2 image description Brent@GMATPrepNow

    GMAT Prep Now Teacher

    96 posts
    3 image description Rich.C@EMPOWERgma...

    EMPOWERgmat

    84 posts
    4 image description DavidG@VeritasPrep

    Veritas Prep

    77 posts
    5 image description Jay@ManhattanReview

    Manhattan Review

    58 posts
    See More Top Beat The GMAT Experts