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Quasi Cylinder Question?


 
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ELYAC Realty
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PostPosted: Sat Aug 30, 2008 12:50 am    Post subject: Quasi Cylinder Question? Reply with quote

Why is pie used if ultimately this is a rectangle? Unless they want us to treat it as a cylinder? Any help would be great.

Thanks

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PostPosted: Sat Aug 30, 2008 2:01 am    Post subject: Re: Quasi Cylinder Question? Reply with quote

ELYAC Realty wrote:
Why is pie used if ultimately this is a rectangle? Unless they want us to treat it as a cylinder? Any help would be great.

Thanks


Because everyone loves pie!

Very Happy

Well, ok, because this isn't a rectangle.

The belt is wrapped around two semi-circles, so the length of the belt is 2 (length "L" between centres of circles) + 2(circumference of semi-circle).

We know that the diameter of each circle is 1, so the circumference of a full circle (which is the same as 2*(circumference of each semicircle)) is pi.

Therefore, we can come up with the equation:

2L + pi = 15
2L = 15 - pi
L = (15 - pi)/2

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ELYAC Realty
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PostPosted: Sat Aug 30, 2008 2:10 am    Post subject: Reply with quote

Thanks for your reply.

When you drawn a vertical line through both circles, doesn't that make it a rectangular?
_______
| |
|______|

something like this, just imagine the lines are all straight. Is that all they want to know?

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Stuart Kovinsky
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PostPosted: Sat Aug 30, 2008 7:56 am    Post subject: Reply with quote

ELYAC Realty wrote:
Thanks for your reply.

When you drawn a vertical line through both circles, doesn't that make it a rectangular?
_______
| |
|______|

something like this, just imagine the lines are all straight. Is that all they want to know?


You could draw a rectangle, but since the belt goes around the circles, not through them, the rectangle is irrelevant to the question.

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ELYAC Realty
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PostPosted: Sat Aug 30, 2008 9:09 am    Post subject: Reply with quote

I guess my confussion was with the questions. Bc my understanding was that they want the distance from one point to the next, which turns out to be the length of "L", but then you wold have to subtract the circumference of 2 half circles or one full circle. Got it. Thanks!
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