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## QG11 Question: 144 DS

This topic has 1 member reply
nuku888 Newbie | Next Rank: 10 Posts
Joined
19 Apr 2007
Posted:
5 messages

#### QG11 Question: 144 DS

Mon Apr 30, 2007 2:26 pm
Elapsed Time: 00:00
• Lap #[LAPCOUNT] ([LAPTIME])
For the second statment:

I multiplied both sides by 10 hence I got 1^n-1 > 1 and because one is equivilant to 1^1 I dropped the 1's and was left with:

n-1 > 1 --> n > 2 which is the same as the first statement

Is this the right way of doing it or was it a fluke? can I do this question this way instead of like the back of the book by trying 1 and 2 first.

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f2001290 Master | Next Rank: 500 Posts
Joined
10 Mar 2007
Posted:
400 messages
Followed by:
1 members
Thanked:
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Wed May 02, 2007 4:09 am
I can't see the question. Could you please post it again?

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