Q. A certain characteristic in a large population has a distribution that is symmetric about the mean (m). If 68% of the distribution lies within one standard deviation (d) of the mean, what percent of the distribution is less than m+d?
A) 16%
B) 32%
C) 48%
D) 84%
E) 92%
Q.112 GMAT OG 13th Edition
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Hi Priyaranjan,
The broad concepts of 'normal distribution' and 'standard deviation' usually show up just 1 time on the GMAT. The "math" is based on a Bell Curve and is a standard concept in most Statistics classes.
With a Bell Curve, 50% of the data points are below the Mean and 50% are above it. Here, we're told that 68% of the data is within on Standard Deviation of the Mean - this means that 34% of THIS data is below the Mean and 34% is above the Mean.
From an organizational standpoint, the data is "spread out" like this:
16% - more than 1 SD below the Mean
34% - within 1 SD below the Mean
34% - within 1 SD above the Mean
16% - more than 1 SD above the Mean
The question asks for the percent of the data that is LESS than (Mean+ 1 SD). Looking at the above information, that would be....
16 + 34 + 34 = 84%
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
The broad concepts of 'normal distribution' and 'standard deviation' usually show up just 1 time on the GMAT. The "math" is based on a Bell Curve and is a standard concept in most Statistics classes.
With a Bell Curve, 50% of the data points are below the Mean and 50% are above it. Here, we're told that 68% of the data is within on Standard Deviation of the Mean - this means that 34% of THIS data is below the Mean and 34% is above the Mean.
From an organizational standpoint, the data is "spread out" like this:
16% - more than 1 SD below the Mean
34% - within 1 SD below the Mean
34% - within 1 SD above the Mean
16% - more than 1 SD above the Mean
The question asks for the percent of the data that is LESS than (Mean+ 1 SD). Looking at the above information, that would be....
16 + 34 + 34 = 84%
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
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Let:Priyaranjan wrote:Q. A certain characteristic in a large population has a distribution that is symmetric about the mean (m). If 68% of the distribution lies within one standard deviation (d) of the mean, what percent of the distribution is less than m+d?
A) 16%
B) 32%
C) 48%
D) 84%
E) 92%
Mean m=10.
Standard deviation d=2.
One SD below the mean = m-d = 10-2 = 8.
One SD above the mean = m+d = 10+2 = 12.
The distribution must be symmetric about the mean of 10.
Since 68% of the distribution lies within one SD of the mean, 34% lies one SD below the mean of 10, and 34% lies one SD above the mean of 10.
The distribution looks like this:
-----16%-----8-----34%-----m=10-----34%-----12-----16%-----
Notice that 50% of the distribution is below the mean of 10, with the remaining 50% above the mean of 10, yielding the required symmetry about the mean.
Since m+d = 10+2 = 12, the portion in red is less than m+d:
16% + 34% + 34% = 84%.
The correct answer is D.
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The information provided tells us that the data making up this distribution is symmetrically distributed about the mean and that 68 percent of the data is within one standard deviation of the mean.Priyaranjan wrote:Q. A certain characteristic in a large population has a distribution that is symmetric about the mean (m). If 68% of the distribution lies within one standard deviation (d) of the mean, what percent of the distribution is less than m+d?
A) 16%
B) 32%
C) 48%
D) 84%
E) 92%
Since we know that the data is symmetrically distributed we know that half of the data is below the mean, and half of the data is above the mean.
Similarly half the the 68 percent of the data that is within one standard deviation of the mean is below the mean, and the other half is above the mean.
The rest of the data, 100 - 68 = 32 percent of the data, is outside that one standard deviation, and half of that is above the mean, and above m + d, and half of that is below them mean, and below m - d.
When the question asks for the percentage of the data below m + d, it is asking for everything but that part of the data that is above m + d.
We know that 32 percent is outside of one standard deviation and half of that is above m + d.
32/2 percent = 16 percent above m + d.
The rest of the data is below m + d. How much? 100 - 16 = 84 percent of the data is below m + d.
Choose D.
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An easier way:
68% is within one SD of the mean. That means that 32% is NOT within one SD. Half of that (16%) will be on the low end, half (16%) on the high end. We want the whole 68% PLUS the low end, or 68% + 16% = 84%.
Visually, that would look like:
|---(low: 16%)---|---------(within one SD: 68%)---------|---(high: 16%)---|
68% is within one SD of the mean. That means that 32% is NOT within one SD. Half of that (16%) will be on the low end, half (16%) on the high end. We want the whole 68% PLUS the low end, or 68% + 16% = 84%.
Visually, that would look like:
|---(low: 16%)---|---------(within one SD: 68%)---------|---(high: 16%)---|
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Solution:Priyaranjan wrote:Q. A certain characteristic in a large population has a distribution that is symmetric about the mean (m). If 68% of the distribution lies within one standard deviation (d) of the mean, what percent of the distribution is less than m+d?
A) 16%
B) 32%
C) 48%
D) 84%
E) 92%
This problem is testing us on the Empirical rule.
In all normal distributions, the Empirical Rule tells us that:
1. About 68 percent of all data values will fall within 1 standard deviation of the mean.
2. About 95 percent of all data values will fall within 2 standard deviations of the mean.
3. About 99.7 percent of all data values will fall within 3 standard deviations of the mean.
It's important to note that, for example, one standard deviation within the mean refers to the data that exists from one standard deviation below the mean to one standard deviation above the mean. Similarly, two standard deviations within the mean refers to the data that exist from two standard deviations below the mean to two standard deviations above the mean.
This is a sketch of a representative normal curve, with the Empirical Rule displayed. The red area indicates the entire part of the curve that is less than (m+d) standard deviations above the mean.
In this particular problem we are being asked what percent of the distribution is less than m + d. We have denoted this on the diagram above. If we add all the percentages in the regions where the red arrows point, we have:
34% + 34% + 13.5% + 2.4 + 0.1 % = 84%
This represents the percent of the distribution that is less than m + d.
Another way to look at this problem is to first see that m is exactly in the middle of the curve; thus, 50% of the data points are below m and 50% are above m. From the Empirical Rule we know that 68% of the data points are within one standard deviation of the mean. This means that 68% of the distribution is between m - d and m + d. Furthermore this means that only 68%/2 = 34% of the distribution is between m and m + d.
We are asked what percent of the distribution is less than m + d (or less than one standard deviation above the mean). Since 50% of the data points are less than m, and 34% of the data points are between m and m + d, we see that 50% + 34% = 84% of the data points (that is, 84% of the distribution) is less than m + d.
The answer is D
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Be careful, Jeff. We're not told that this is a Normal distribution. So, it might not be the case that 95 percent of all data values will fall within 2 standard deviations of the mean etc.Jeff@TargetTestPrep wrote: Solution:
This problem is testing us on the Empirical rule.
In all normal distributions, the Empirical Rule tells us that:
1. About 68 percent of all data values will fall within 1 standard deviation of the mean.
2. About 95 percent of all data values will fall within 2 standard deviations of the mean.
3. About 99.7 percent of all data values will fall within 3 standard deviations of the mean.
This one relies strictly on the fact that the distribution is symmetric about the mean.
Cheers,
Brent