PS Problem from GMATPrep

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Tsadori
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Topic: PS Problem from GMATPrep
PostSun Jan 21, 2007 3:15 pm

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g2000
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PostSun Jan 21, 2007 4:44 pm

40 = Circumference of square + perimeter of square

We are to find the sum of areas of both.
Area of circle = pi * r^2
Area of Square = m^2 where m is the one side length of square

4*m = 40 - (2 * pi * r)
m = ( 40 - (2 * pi * r) ) / 4
m = (10 - ((pi * r ) / 2 ) )

Total area enclosed by both shapes
= area of circle + area of square
= (pi * r ^ 2) + (10 - (( pi * r)/ 2)) ^ 2

Answer is the last choice
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Tsadori
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PostMon Jan 22, 2007 3:15 pm

OA: E

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