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f2001290 GMAT Destroyer!

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Posted: Mon Jun 11, 2007 12:40 am Post subject: PS - Probability |
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How many number of 3 digit numbers can be formed with the digits 0,1,2,3,4,5 if no digit is repeated in any number? How many of these are even and how many odd?
I am getting even and odd numbers as 52 and 48.
But this is not the OA. |
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Neo2000 Moderator

Joined: 27 Jan 2007 Posts: 366
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Location: India Test Date: 30/09 Target GMAT Score: 710
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Posted: Mon Jun 11, 2007 8:19 am Post subject: |
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To create 3 digit numbers
The first place can be filled in 5ways only (from 1,2,3,4 or 5 let's say 5)
The second place can be filled in 5ways (from 0,1,2,3 or 4 let's say 1)
The third place can be filled in 4 ways ( from 0,2,3 or 4)
So total number of ways of creating 3digit numbers without repetition = 5x5x4 = 100
Exactly half of this will be Odd and half will be Even |
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f2001290 GMAT Destroyer!

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Posted: Mon Jun 11, 2007 9:04 am Post subject: |
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Neo
first part is right, but the OA of second part is 60 and 40. |
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Neo2000 Moderator

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Posted: Mon Jun 11, 2007 9:18 am Post subject: |
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My bad
To Create 3 digit odd numbers
The last place can be filled in 3 ways 1,3,5 lets say 1
The first place can be filled in 4
The second place can be filled in 4ways
So total = 4x4x3 = 48
Which means there are 52 Even numbers |
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jayhawk2001 Moderator

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Posted: Mon Jun 11, 2007 11:12 am Post subject: |
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There are 6P3 - 5P2 numbers in all = 120 - 20 = 100 numbers.
Of this 4*4*3 = 48 are odd and 52 are even (same approach as Neo's) |
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