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Probability Question

This topic has 4 expert replies and 3 member replies
chiphipoke Newbie | Next Rank: 10 Posts Default Avatar
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Posted:
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Probability Question

Post Mon Jan 13, 2014 8:22 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    Of the 20 members of a kitchen crew, 17 can use the meat-cutting machine, 18 can use the bread-slicing machine, and 15 can use both machines. If one member of the crew is to be chose at random, what is the probability that the member chosen will be someone who cannot use either machine?


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    This question is from GMATPrep's Exam Pack 3 and I cannot solve it for the life of me. Please provide an explanation. Thanks!

    Answer is A

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    theCodeToGMAT Legendary Member
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    Post Mon Jan 13, 2014 9:37 am
    Use a Matrix Method..
    Black ones are from question
    Green ones are implied
    Red Box is what we need to find.

    {A}
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    coreyj808 Newbie | Next Rank: 10 Posts Default Avatar
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    Post Mon Jan 13, 2014 11:39 am
    I agree, you need to take your time on this or it's very easy to make a mistake.

    Think of it like a box where you are adding up numbers to get to 20.

    So you know the people who can use both machines is 15 - this tells us that there is an overlap of 15 for both sides.

    [ 15 ]

    Then, we look at meat cutters (17), so the excess would be 2

    [ 15 ]+[ 2 Meat cutters]

    and then the difference between both and Bread makers which equals 3

    [ 15 both ]+[ 2MC ]+[ 3BM ] = [ 20 total ]

    Since the total is 20, there is no way that you could not pick someone that is not qualified in either. Hope this helps!

    Thanked by: chiphipoke
    Post Mon Jan 13, 2014 12:08 pm
    chiphipoke wrote:
    Of the 20 members of a kitchen crew, 17 can use the meat-cutting machine, 18 can use the bread-slicing machine, and 15 can use both machines. If one member of the crew is to be chose at random, what is the probability that the member chosen will be someone who cannot use either machine?


      0
      1/10
      1/7
      1/4
      1/3

    We can use the following formula for two overlapping groups:

    Total = Group 1 + Group 2 - Both + Neither.

    The big idea with overlapping groups is to SUBTRACT THE OVERLAP.
    When we count everyone in Group 1 (meat-cutters) and everyone in Group 2 (bread-slicers), those in BOTH groups (members who can use BOTH types of machines) get counted twice.
    So that we don't double-count the members in both groups, we SUBTRACT THE OVERLAP from the total.

    In the problem at hand:
    Total = 20.
    Group 1 = meat-cutters = 17.
    Group 2 = bread-slicers = 18.
    Both = 15.
    Let N = the number who can use neither type of machine.

    Plugging these values into the equation above, we get:
    20 = 17 + 18 - 15 + N
    N = 0.

    Since 0 members can use neither type of machine, P(selecting a member who can use neither type of machine) = 0.

    The correct answer is A.

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    Post Mon Jan 13, 2014 12:38 pm
    theCodeToGMAT wrote:
    Use a Matrix Method..
    Black ones are from question
    Green ones are implied
    Red Box is what we need to find.

    {A}
    A note to those who are unfamiliar with the "(Double) Matrix Method": This technique can be used for most questions featuring a population in which each member has two characteristics associated with it.
    Here, we have a population of kitchen crew members, and the two characteristics are:
    - CAN use the meat-cutting machine and CANNOT use the meat-cutting machine
    - CAN use the bread-slicing machine and CANNOT use the bread-slicing machine

    To learn more about this technique, watch our free video: http://www.gmatprepnow.com/module/gmat-word-problems?id=919

    Then try these additional practice questions that can be solved using the Double Matrix Method:
    - http://www.beatthegmat.com/mba/2011/05/05/random-double-matrix-question-1
    - http://www.beatthegmat.com/mba/2011/05/09/random-double-matrix-question-2
    - http://www.beatthegmat.com/mba/2011/05/16/random-double-matrix-question-3
    - http://www.beatthegmat.com/ds-quest-t187706.html
    - http://www.beatthegmat.com/overlapping-sets-questions-t183320.html
    - http://www.beatthegmat.com/finance-majors-non-finance-majors-overlapping-set-question-t167425.html
    - http://www.beatthegmat.com/ds-french-japanese-t222297.html
    - http://www.beatthegmat.com/sets-t269449.html#692540
    - http://www.beatthegmat.com/in-costume-for-halloween-t269355.html#692116

    Cheers,
    Brent

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    Post Wed Jan 15, 2014 12:15 pm
    One last tip: even if you're completely lost on test day, you KNOW the answer can't be (C) or (E) because you can't have (1/7) or (1/3) of a group of 20 people - no fractional persons allowed! You know that the answer can't be (1/4): since you have 18 people out of 20 who can use the bread slicer, you have AT MOST 2 people (or 1/10 of the total) who can't use either machine.

    With that, you know the answer is either A or B, and you have a 50% chance of getting the question right! Pretty cool, and almost more satisfying than actually knowing how to solve. Very Happy

    chiphipoke wrote:
    Of the 20 members of a kitchen crew, 17 can use the meat-cutting machine, 18 can use the bread-slicing machine, and 15 can use both machines. If one member of the crew is to be chose at random, what is the probability that the member chosen will be someone who cannot use either machine?


      0
      1/10
      1/7
      1/4
      1/3


    This question is from GMATPrep's Exam Pack 3 and I cannot solve it for the life of me. Please provide an explanation. Thanks!

    Answer is A

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    petrorich Newbie | Next Rank: 10 Posts Default Avatar
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    Posted:
    3 messages
    Post Tue Jun 23, 2015 8:37 am
    I was racking my brain on this problem, until I figured out you can use a Venn Diagram to make life easier!!

    Had I not been so narrow-minded and always trying to solve problems using ONLY 1 method, I would have gotten this within seconds!


    ttp://postimg.org/image/7cd3onccf/" target="_blank">

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    Post Tue Jun 23, 2015 6:01 pm
    Petro, that's a great idea: any time you have two groups with some overlap, a Venn (or a matrix) is a lifesaver.

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