OG 11 DS Question 148

This topic has expert replies
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Thu Apr 19, 2007 5:20 pm

OG 11 DS Question 148

by nuku888 » Thu Apr 26, 2007 5:52 pm
Hello,

I was wondering if anyone could help me with this question. I read the explanation at the back but I don't really understand it.

The question is:

What is the tens digit of the positive integer x?

1. X divided by 100 has a remainder of 30
2. X divided by 110 has a remainder of 30

What is the fastest way to find the what # gives you a remainder of 30 for statement 2? Or do I have to find it through trial and error?

Also can anyone give me some tips on how to do these remainder questions I always mess up on them.

User avatar
Master | Next Rank: 500 Posts
Posts: 400
Joined: Sat Mar 10, 2007 4:04 am
Thanked: 1 times
Followed by:1 members

by f2001290 » Thu Apr 26, 2007 8:36 pm
Hi Nuku

What is the solution ? I think that the answer is A

I prefer trial and error for the second option.

Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Thu Apr 19, 2007 5:20 pm

by nuku888 » Mon Apr 30, 2007 2:18 pm
Yups the answer is A

User avatar
Community Manager
Posts: 789
Joined: Sun Jan 28, 2007 3:51 pm
Location: Silicon valley, California
Thanked: 30 times
Followed by:1 members

Re: OG 11 DS Question 148

by jayhawk2001 » Mon Apr 30, 2007 9:20 pm
nuku888 wrote:Hello,

I was wondering if anyone could help me with this question. I read the explanation at the back but I don't really understand it.

The question is:

What is the tens digit of the positive integer x?

1. X divided by 100 has a remainder of 30
2. X divided by 110 has a remainder of 30

What is the fastest way to find the what # gives you a remainder of 30 for statement 2? Or do I have to find it through trial and error?

Also can anyone give me some tips on how to do these remainder questions I always mess up on them.
1 - Sufficient. X = 100n + 30. So tens digit has to be 3.

2 - Insufficient. X = 110n + 30 = 100n + 10n + 30. So, tens digit
depends on n, which we don't know

Hence A