John traveled the entire 60 miles tirp. if he did the first 12 miles of a constant rate 24 miles per hour and the remaining trip of a constant rate 48 miles per hour, what is the his average speed, in miles per hour?
A. 20 mph
B. 24 mph
C. 30 mph
D. 32 mph
E. 40 mph
The OA is E.
Is there a strategic approach to this PS question? Can any experts help, please?
I know that average speed will be, total distance / total time, but i don't know how can I do or how can I solve this question. I need your help. Thanks!
John traveled the entire 60 miles trip. If he did the...
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Well, you could do the math.AAPL wrote:John traveled the entire 60 miles tirp. if he did the first 12 miles of a constant rate 24 miles per hour and the remaining trip of a constant rate 48 miles per hour, what is the his average speed, in miles per hour?
A. 20 mph
B. 24 mph
C. 30 mph
D. 32 mph
E. 40 mph
The OA is E.
Is there a strategic approach to this PS question? Can any experts help, please?
I know that average speed will be, total distance / total time, but i don't know how can I do or how can I solve this question. I need your help. Thanks!
First part of trip: it'll take 1/2 hour to go 12 miles at 24 mph.
Second part of trip: There are 60-12 = 48miles remaining. It'll take 1 hour to cover those 48 miles at 48mph.
Total distance:60
Total time: 1/2 + 1 = 1/5 hours
Avg rate: 60/1.5 = 40 mph. The answer is E
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But you can see that if John spent the same amount of time traveling at 24mph and at 48mph, he'd have traveled at (24 + 48)/2 = 72/2 = 36 mph. So long as you see that he spent more time traveling at 48mph than at 24 mph, we know his average would have been pulled towards the faster speed, and thus that average would to be greater than 36 mph. Only E works.AAPL wrote:John traveled the entire 60 miles tirp. if he did the first 12 miles of a constant rate 24 miles per hour and the remaining trip of a constant rate 48 miles per hour, what is the his average speed, in miles per hour?
A. 20 mph
B. 24 mph
C. 30 mph
D. 32 mph
E. 40 mph
The OA is E.
Is there a strategic approach to this PS question? Can any experts help, please?
I know that average speed will be, total distance / total time, but i don't know how can I do or how can I solve this question. I need your help. Thanks!
12 miles at 24 mph = 30 mins.AAPL wrote:John traveled the entire 60 miles tirp. if he did the first 12 miles of a constant rate 24 miles per hour and the remaining trip of a constant rate 48 miles per hour, what is the his average speed, in miles per hour?
A. 20 mph
B. 24 mph
C. 30 mph
D. 32 mph
E. 40 mph
The OA is E.
Is there a strategic approach to this PS question? Can any experts help, please?
I know that average speed will be, total distance / total time, but i don't know how can I do or how can I solve this question. I need your help. Thanks!
48 miles at 48 mph = 60 mins.
Total time taken = 30+60 = 90 mins.
Total distance = 60 miles.
Average speed = (60/90) * 60 = 40 mph.
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Hi AAPL,
We're told that John tool a 60 miles trip; the first 12 miles of a constant rate 24 miles per hour and the remaining distance at a constant rate 48 miles per hour. We're asked for the average speed, in miles per hour, for the entire trip. To answer this question, you might find it easiest to break the calculation down into 'pieces.'
1st part of the trip: 12 miles at 24 miles/hour....
Distance = (Rate)(Time)
12 miles = (24 mi/hour)(T)
12/24 = T
T = 1/2 hour
2nd part of the trip: 48 miles at 48 miles/hour....
Distance = (Rate)(Time)
48 miles = (48 mi/hour)(T)
48/48 = T
T = 1 hour
Total Distance = 60 miles
Total Time = 1.5 hours
Total Distance = (Av. Speed)(Total Time)
60 miles = (X)(1.5 hours)
60/1.5 = X
120/3 = X
X = 40 miles per hour
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
We're told that John tool a 60 miles trip; the first 12 miles of a constant rate 24 miles per hour and the remaining distance at a constant rate 48 miles per hour. We're asked for the average speed, in miles per hour, for the entire trip. To answer this question, you might find it easiest to break the calculation down into 'pieces.'
1st part of the trip: 12 miles at 24 miles/hour....
Distance = (Rate)(Time)
12 miles = (24 mi/hour)(T)
12/24 = T
T = 1/2 hour
2nd part of the trip: 48 miles at 48 miles/hour....
Distance = (Rate)(Time)
48 miles = (48 mi/hour)(T)
48/48 = T
T = 1 hour
Total Distance = 60 miles
Total Time = 1.5 hours
Total Distance = (Av. Speed)(Total Time)
60 miles = (X)(1.5 hours)
60/1.5 = X
120/3 = X
X = 40 miles per hour
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
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We can use the formula:AAPL wrote:John traveled the entire 60 miles tirp. if he did the first 12 miles of a constant rate 24 miles per hour and the remaining trip of a constant rate 48 miles per hour, what is the his average speed, in miles per hour?
A. 20 mph
B. 24 mph
C. 30 mph
D. 32 mph
E. 40 mph
Average speed = (total distance/total time)
The time for the first 12 miles was 12/24 = 0.5 hour.
The time for the remaining 48 miles was 48/48 = 1 hour.
Thus:
Average speed = 60/1.5 = 40 mph
Answer: E
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If you're doing a lot of math, chances are you're doing something wrong. The Quant part of the GMAT isn't a math test -- it's a test of reasoning ability.
If you travel half of the trip at 24 mph and the other half at 48 mph, then you will average 36 mph. However, John only did 12 miles of 60 miles at the slow speed. Granted, it's about the TIME spent not the DISTANCE, but even so, it's obvious that the answer must be greater than 36 mph. There is only one choice that is greater than 36 mph, and that's (E). Next problem!
If you travel half of the trip at 24 mph and the other half at 48 mph, then you will average 36 mph. However, John only did 12 miles of 60 miles at the slow speed. Granted, it's about the TIME spent not the DISTANCE, but even so, it's obvious that the answer must be greater than 36 mph. There is only one choice that is greater than 36 mph, and that's (E). Next problem!
Elias Latour
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+1 (646) 736-7622
Verbal Specialist @ ApexGMAT
blog.apexgmat.com
+1 (646) 736-7622