Roses can be purchased individually for $4.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?
A. 156
B. 162
C. 318
D. 324
E. 325
The OA is C.
Please, can any expert explain this PS question for me? I can't get the correct answer. I need your help. Thanks.
Roses can be purchased individually for $4.30...
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- DavidG@VeritasPrep
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If we're trying to maximize the number of roses, we want to purchase as many roses as possible in bundles of two dozen, as that's the best deal.swerve wrote:Roses can be purchased individually for $4.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?
A. 156
B. 162
C. 318
D. 324
E. 325
The OA is C.
Please, can any expert explain this PS question for me? I can't get the correct answer. I need your help. Thanks.
If we're paying $50 for each bouquet of two-dozen, then the most we can spend on these bouquets is $650, as this is the largest multiple of 50 under 680. 50 goes into 650 13 times. So for $650, we can buy 13 bouquets of 24 flowers each, or 24*13 = 312 flowers.
A and B are out.
We've got $30 left to spend. Clearly we can't afford the dozen roses for $36. If we can't afford 12 more roses then the correct answer must be less than 324 (As 312 + 12 = 324.) Eliminate D and E.
We're left with C. No need to do more math.
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- Scott@TargetTestPrep
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Note first that the cheapest price per rose is obtained by buying a 2-dozen bouquet. Thus, we want to buy as many 2-dozen bouquets as possible.swerve wrote:Roses can be purchased individually for $4.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?
A. 156
B. 162
C. 318
D. 324
E. 325
Since 650/50 = 13, 13 x 24 = 312 roses can be purchased for 650 dollars when buying them 2 dozen at a time.
With the remaining 30 dollars, 6 more roses can be purchased, for a total of 318 roses.
Answer: C
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