How many multiples of 4 are there between 12 and 96, inclusive?
a. 21
b. 22
c. 23
d. 24
e. 25
didn't know where to begin with this one either... this is the last question out of my problem set that I did not get... if you'll notice there's a theme with the questions I've just posted... all the same topic... Exponents, Odds & Evens, Postives, Negatives, and Roots were all easy for me... ::sigh::
OA B
Multiples of 4 between 12 and 96
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- money9111
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How many multiples of 4 are there between 12 and 96, inclusive?
a. 21
b. 22
c. 23
d. 24
e. 25
Multiples of 4 are : 12, 16, 20, 24, ........, 96
for a evenly spaced set: total no of terms = (last - first)/increment
= 96-12/4
= 21
as the question ask for inclusive = 21+1 =22
a. 21
b. 22
c. 23
d. 24
e. 25
Multiples of 4 are : 12, 16, 20, 24, ........, 96
for a evenly spaced set: total no of terms = (last - first)/increment
= 96-12/4
= 21
as the question ask for inclusive = 21+1 =22
- money9111
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ah ha... "Last-First/increment"... going in my notecards... thanks!
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no.Cally627 wrote:quick question,
if the problem mentions "inclusive" - we add the 1.
large - small / 2 + 1
if the problem doesn't mention inclusive - do we not add the 1?
thanks.
as for the q. above it can be solved this way-
((96-12)/4) +1=22
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If you'd rather not memorize formulas, you can also try listing and looking for a pattern.money9111 wrote:How many multiples of 4 are there between 12 and 96, inclusive?
a. 21
b. 22
c. 23
d. 24
e. 25
Let's list the multiples of 4 from 12 to 96 inclusive.
12 = 4(3)
16 = 4(4)
20 = 4(5)
24 = 4(6)
.
.
.
88 = 4(22)
92 = 4(23)
96 = 4(24)
As you can see, the number of multiples of 4 from 12 to 96 inclusive is equal to the number of integers from 3 to 24 inclusive.
Well, we know that the number from integers from x to y inclusive equals y - x + 1
So, the number of integers from 3 to 24 inclusive equals 24 - 3 + 1 = 22
Answer: B
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Hi All,
Certain versions of these questions can be solved by including (and then removing) elements to "round out" the math.
In this case, it would be pretty easy to count the multiples of 4 from 1 to 100: there are 25 of them......25(4) = 100
So, which multiples of 4 must we REMOVE from this group of 25?
We want 12 to 96, inclusive, so we should REMOVE: 4, 8, 100. That's 3 values.
25 - 3 = 22
Final Answer:B
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Certain versions of these questions can be solved by including (and then removing) elements to "round out" the math.
In this case, it would be pretty easy to count the multiples of 4 from 1 to 100: there are 25 of them......25(4) = 100
So, which multiples of 4 must we REMOVE from this group of 25?
We want 12 to 96, inclusive, so we should REMOVE: 4, 8, 100. That's 3 values.
25 - 3 = 22
Final Answer:B
GMAT assassins aren't born, they're made,
Rich
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We can determine the multiples of 4 from 12 to 96 (inclusive) by using the following formula:money9111 wrote:How many multiples of 4 are there between 12 and 96, inclusive?
a. 21
b. 22
c. 23
d. 24
e. 25
(largest multiple of 4 - smallest multiple of 4)/4 + 1
(96 - 12)/4 + 1 =84/4 + 1 = 21 + 1 = 22
Answer: B
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