Set A consists of integers -9, 8, 3, 10, and J; Set B consists of integers -2, 5, 0, 7, -6, and T. If R is the median of Set A and W is the mode of set B, and R^W is a factor of 34, what is the value of T if J is negative?
(A) -2
(B) 0
(C) 1
(D) 2
(E) 5
OA is b
I cannot really get the mathematical approach to this question. can any expert help me out?
Thanks in advance for your help
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Set A: -9, J, 3, 8, 10,. We know R is the median here; We're dealing with a scenario in which J is negative, so 3, must be the median.Roland2rule wrote:Set A consists of integers -9, 8, 3, 10, and J; Set B consists of integers -2, 5, 0, 7, -6, and T. If R is the median of Set A and W is the mode of set B, and R^W is a factor of 34, what is the value of T if J is negative?
(A) -2
(B) 0
(C) 1
(D) 2
(E) 5
OA is b
I cannot really get the mathematical approach to this question. can any expert help me out?
Thanks in advance for your help
If R^W is a factor of 34, then W must be 0, as 3 is itself not a factor of 34.
Set B: -6, -2, 0, 5, 7, and T. If the mode of set B is W, and W = 0, then T has to be 0. The answer is B
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Since J is negative, the median of the set A is 3; thus, R = 3.BTGmoderatorRO wrote:Set A consists of integers -9, 8, 3, 10, and J; Set B consists of integers -2, 5, 0, 7, -6, and T. If R is the median of Set A and W is the mode of set B, and R^W is a factor of 34, what is the value of T if J is negative?
(A) -2
(B) 0
(C) 1
(D) 2
(E) 5
OA is b
I cannot really get the mathematical approach to this question. can any expert help me out?
Thanks in advance for your help
We are told that R^W = 3^W is a factor of 34 = 2 * 17; this is only possible if W = 0.
Finally, since W = 0 is the mode of set B, there must be more than one occurrence of 0 in set B. Therefore, T must be 0.
Answer: B
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