If ⌈x⌉ denotes the least integer greater than or equal to x, is ⌈x⌉=0 ?
1. -1 < x < 1
2. x < 0
OG 18, question-364
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S1: pick some numbers in the rangevaibhav101 wrote:If ⌈x⌉ denotes the least integer greater than or equal to x, is ⌈x⌉=0 ?
1. -1 < x < 1
2. x < 0
Case 1: x = -1/2; If {-1/2] denotes the least integer greater than or equal to -1/2, then {-1/2] would be 0. So we get a YES. (Effectively, if x isn't an integer, we're just rounding up to the closest integer.)
Case 2: x = 1/2; If {1/2] denotes the least integer greater than or equal to 1/2, then {1/2] would be 1. So we get a NO. Not sufficient.
S2: Clearly not sufficient. x could be -1/2. Or x could be -100.
Together: Now we know that -1 < x < 0. No matter what value we pick for x, the smallest integer greater than x will be 0. (If x = -1/2 we round up to 0. If x = -1/8 we round up to 0, etc.) The answer is definitely YES, so together the statements are sufficient. The answer is C
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Here are a couple of related questions to practice with:
- https://www.beatthegmat.com/clarity-need ... 67353.html
- https://www.beatthegmat.com/ds-t276593.html
Cheers,
Brent
- https://www.beatthegmat.com/clarity-need ... 67353.html
- https://www.beatthegmat.com/ds-t276593.html
Cheers,
Brent
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Another tip: reformat the stem into something familiar so that your mind doesn't keep wandering back to the unfamiliar symbol. If we grapple with the prompt for a bit, then rephrase this as
the statements are a cinch, but if we don't, it's easy to keep staring at that ceiling function and doubting ourselves.Is -1 < x ≤ 0 ?