Q.1 A man buys 2 dozen bananas at $16 per dozen. After selling 18 bananas at the rate of $12 per dozen, the shopkeeper reduced the rate to $4 per dozen. The % loss is
A 25.2
B 34.2
C 36.5
D 37.5
E 40
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Profit and loss
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vaibhav101
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Jay@ManhattanReview
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Hi vaibhav101,
Pl. post each of the three questions as a separate post.
-Jay
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Pl. post each of the three questions as a separate post.
-Jay
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[email protected]
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Hi vaibhav101,
A 'dozen' is 12, so since this question organizes all of its information in terms of 'dozens', you can either focus on that unit of measure or work on a 'per banana' calculation. Here's how you can focus on dozens of bananas at a time:
We're told that 2 dozen bananas are purchased for $16/dozen. That's a cost of...
(2)($16) = $32 to purchase the 2 dozen bananas
Then we're told the prices that the bananas were sold for:
18 bananas = 1.5 dozen at $12/dozen = (1.5)($12) = $18
6 bananas = 1/2 dozen at $4/dozen = (.5)($4) = $2
Total revenue = $18 + $2 = $20
The question asks for "% loss", which implies the percent change in revenue relative to cost.
(Revenue - Cost)/(Cost) = (20 - 32)/32 = -12/32 = - 3/8 = -37.5%
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
A 'dozen' is 12, so since this question organizes all of its information in terms of 'dozens', you can either focus on that unit of measure or work on a 'per banana' calculation. Here's how you can focus on dozens of bananas at a time:
We're told that 2 dozen bananas are purchased for $16/dozen. That's a cost of...
(2)($16) = $32 to purchase the 2 dozen bananas
Then we're told the prices that the bananas were sold for:
18 bananas = 1.5 dozen at $12/dozen = (1.5)($12) = $18
6 bananas = 1/2 dozen at $4/dozen = (.5)($4) = $2
Total revenue = $18 + $2 = $20
The question asks for "% loss", which implies the percent change in revenue relative to cost.
(Revenue - Cost)/(Cost) = (20 - 32)/32 = -12/32 = - 3/8 = -37.5%
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
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DavidG@VeritasPrep
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You can also treat this as a weighted average.vaibhav101 wrote:Q.1 A man buys 2 dozen bananas at $16 per dozen. After selling 18 bananas at the rate of $12 per dozen, the shopkeeper reduced the rate to $4 per dozen. The % loss is
A 25.2
B 34.2
C 36.5
D 37.5
E 40
Loss on bananas bought for $16/dozen and sold for $12/dozen = (16-12)/16 = 25%
Loss on bananas bought for $16/dozen and sold for $4/dozen = (16-4)/16 = 75%
18 bananas were sold at $12/dozen and the remaining 6 were sold at $4/dozen. So there were three times as many bananas sold at a 25% loss than at a 75% loss. Call the distance between each loss and the average loss, 'x' and '3x.'
25---------Average Loss------------------75
Gap: x----------------------------3x---------
Distance from 25 to 75 = 50. x + 3x = 4x.
4x = 50 and x = 12.5
25 + 12.5 = 37.5. The answer is D
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Matt@VeritasPrep
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He paid 2 * $16, or $32.
He got back 1.5 * $12 + 0.5 * $4, or $20.
He ended up with 20/32, or 5/8 of what he started with, meaning that he lost 3/8, or 37.5%.
He got back 1.5 * $12 + 0.5 * $4, or $20.
He ended up with 20/32, or 5/8 of what he started with, meaning that he lost 3/8, or 37.5%.
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Jeff@TargetTestPrep
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We are given that a man buys 2 dozen bananas for $16, so he pays $32.vaibhav101 wrote:Q.1 A man buys 2 dozen bananas at $16 per dozen. After selling 18 bananas at the rate of $12 per dozen, the shopkeeper reduced the rate to $4 per dozen. The % loss is
A 25.2
B 34.2
C 36.5
D 37.5
E 40
He sells 18 bananas, or 1.5 dozen bananas, for $12 per dozen, so he receives a total of 1.5 x 12 = $18.
Since he reduces the price per dozen to $4, he receives from the sale of the remaining 0.5 dozen bananas 0.5 x 4 = $2.
Thus, he earns 18 + 2 = $20. His loss is 32 - 20 = $12 and the percentage loss is 12/32 = 3/8 = 37.5%.
Answer: D
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