Is x^4 + y^4 > z^4 ?
1. x^2 + y^2 > z^2
2. x + y > z
Source : GMATPrep
OA=E
Is x^4 + y^4 > z^4 ? 1. x^2 + y^2 > z^2 2. x + y >
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Target question: Is x^4 + y^4 > z^4 ?ziyuenlau wrote:Is x^4 + y^4 > z^4 ?
1. x² + y² > z²
2. x + y > z
Statement 1: x² + y² > z²
This statement doesn't FEEL sufficient, so I'll TEST some values.
There are several values of x, y and z that satisfy statement 1. Here are two:
Case a: x = 1, y = 1 and z = 1. This meets the condition that x² + y² > z². In this case, x^4 + y^4 > z^4
Case b: x = 1/2, y = 1/2 and z = 2/3. This meets the condition that x² + y² > z². In this case, x^4 + y^4 < z^4
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Aside: For more on this idea of plugging in values when a statement doesn't feel sufficient, read my article: https://www.gmatprepnow.com/articles/dat ... lug-values
Statement 2: x + y > z
This statement doesn't FEEL sufficient either, so I'll TEST some values.
There are several values of x, y and z that satisfy statement 1. Here are two:
Case a: x = 1, y = 1 and z = 1. This meets the condition that x² + y² > z². In this case, x^4 + y^4 > z^4
Case b: x = 1/2, y = 1/2 and z = 2/3. This meets the condition that x² + y² > z². In this case, x^4 + y^4 < z^4
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
IMPORTANT: Notice that I was able to use the same counter-examples to show that each statement ALONE is not sufficient. So, the same counter-examples will satisfy the two statements COMBINED.
In other words,
Case a: x = 1, y = 1 and z = 1. This meets the condition that x² + y² > z². In this case, x^4 + y^4 > z^4
Case b: x = 1/2, y = 1/2 and z = 2/3. This meets the condition that x² + y² > z². In this case, x^4 + y^4 < z^4
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT
Answer: E
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Brent
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Hi ziyuenlau,
This question can be solved by TESTing VALUES. When a DS prompt involves lots of exponents, it's likely that you'll have to consider values OTHER than positive integers though (including 0, negatives, fractions, etc.).
We're asked if X^4 + Y^4 > Z^4. This is a YES/NO question.
Since Fact 2 is easier to deal with than Fact 1, I'm going to start there (we might also be able to use our work on Fact 2 to more easily deal with Fact 1)....
2) X + Y > Z
IF....
X = 1, Y = 0 and Z = 0, then the answer to the question is YES.
X = 1/2, Y = 1/2 and Z = .7, then the answer to the question is NO.
Fact 2 is INSUFFICIENT
1) X^2 + Y^2 > Z^2
The TESTs that we used in Fact 2 also "fit" the information in Fact 1...
IF....
X = 1, Y = 0 and Z = 0, then the answer to the question is YES.
X = 1/2, Y = 1/2 and Z = .7, then the answer to the question is NO.
Fact 1 is INSUFFICIENT
Combined, we have two sets of numbers that fit both Facts and produce different answers to the given question (one YES and one NO).
Combined, INSUFFICIENT.
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
This question can be solved by TESTing VALUES. When a DS prompt involves lots of exponents, it's likely that you'll have to consider values OTHER than positive integers though (including 0, negatives, fractions, etc.).
We're asked if X^4 + Y^4 > Z^4. This is a YES/NO question.
Since Fact 2 is easier to deal with than Fact 1, I'm going to start there (we might also be able to use our work on Fact 2 to more easily deal with Fact 1)....
2) X + Y > Z
IF....
X = 1, Y = 0 and Z = 0, then the answer to the question is YES.
X = 1/2, Y = 1/2 and Z = .7, then the answer to the question is NO.
Fact 2 is INSUFFICIENT
1) X^2 + Y^2 > Z^2
The TESTs that we used in Fact 2 also "fit" the information in Fact 1...
IF....
X = 1, Y = 0 and Z = 0, then the answer to the question is YES.
X = 1/2, Y = 1/2 and Z = .7, then the answer to the question is NO.
Fact 1 is INSUFFICIENT
Combined, we have two sets of numbers that fit both Facts and produce different answers to the given question (one YES and one NO).
Combined, INSUFFICIENT.
Final Answer: E
GMAT assassins aren't born, they're made,
Rich