If xy = 7 and x - y = 7, then x² + y² =
(A) 35
(B) 42
(C) 49
(D) 56
(E) 63
Source: GMAT Prep Now
Difficulty level: 600 - 650
Answer: E
If xy = 7 and x – y = 7
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Take x - y = 7; Square both sides to get x^2 - 2xy + y^2 = 49Brent@GMATPrepNow wrote:If xy = 7 and x - y = 7, then x² + y² =
(A) 35
(B) 42
(C) 49
(D) 56
(E) 63
Source: GMAT Prep Now
Difficulty level: 600 - 650
Answer: E
If xy = 7, we can substitute 7 in place of xy to get x^2 - 2*7 + y^2 = 49
x^2 - 14 + y^2 = 49 ---> x^2 + y^2 = 63. The answer is E
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We could also look for solutions to x and y, though that's much less fun! Since each term equals 7, we can start by setting them equal to each other.
x - y = xy
Then subtract to get them all on one side:
0 = xy - x + y
Since y = 7/x, we can sub that in:
0 = x*(7/x) - x + (7/x)
Then multiply both sides by x:
0 = 7x - x² + 7
x² - 7x - 7 = 0
Then solve the quadratic, which gives x = 7/2 ± √77/2. Then we know y = -7/2 ± √77/2, since x - y must = 7.
From there, just plug in again, and you're done. Yuck.
x - y = xy
Then subtract to get them all on one side:
0 = xy - x + y
Since y = 7/x, we can sub that in:
0 = x*(7/x) - x + (7/x)
Then multiply both sides by x:
0 = 7x - x² + 7
x² - 7x - 7 = 0
Then solve the quadratic, which gives x = 7/2 ± √77/2. Then we know y = -7/2 ± √77/2, since x - y must = 7.
From there, just plug in again, and you're done. Yuck.