A little help with this one, please?

This topic has expert replies
Junior | Next Rank: 30 Posts
Posts: 28
Joined: Mon Oct 10, 2016 5:38 pm

A little help with this one, please?

by fambrini » Tue Nov 08, 2016 4:45 pm
If y = |x - 2| + |x - 3|, is y = 1?

1) 2 < x < 3

2) x > 2

OA: A

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Tue Nov 08, 2016 5:03 pm
fambrini wrote:If y = |x - 2| + |x - 3|, is y = 1?

1) 2 < x < 3

2) x > 2

OA: A
|a-b| = the DISTANCE between a and b.

Thus:
|x-2| = the distance between x and 2.
|x-3| = the distance between x and 3.
y = the SUM of these two distances.

Question stem rephrased:
Is the sum of the two distances equal to 1?

The distance between 2 and 3 is 1.

Thus, if x is BETWEEN these two endpoints, then the sum of the two distances will be EQUAL TO 1:
2 <--- |x-2| ---> x <---|x-3|---> 3.
As indicated by the blue portion, |x-2| + |x-3| = the distance between 2 and 3 = 1.

By extension, if x is BEYOND either endpoint -- if x is to the left of 2 or to the right of 3 -- then the sum of the two distances will be GREATER THAN 1.

Thus:
y=1 if x is between 2 and 3.
y>1 if x if x<2 or x>3.

Statement 1: 2<x<3
Since x is between 2 and 3, y=1.
SUFFICIENT.

Statement 2: x>2

If x=2.5, then x is between 2 and 3, with the result that y=1.
If x=4, then x is NOT between 2 and 3, with the result that y>1.
INSUFFICIENT.

The correct answer is A.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pm
Location: Palo Alto, CA
Thanked: 2867 times
Followed by:511 members
GMAT Score:800

by [email protected] » Wed Nov 09, 2016 10:50 am
Hi fambrini,

GMAT questions are built around patterns (math rules, formulas, grammar, logic, etc.), so even if you don't initially spot a pattern, you can often do some 'brute force' work to prove that a pattern is there.

We're told that Y = |X - 2| + |X - 3|. We're asked if Y = 1. This is a YES/NO question and this question can be solved by TESTing VALUES.

1) 2 < X < 3

Let's TEST the most obvious value we can think of...
IF... X = 2.5
|2.5 - 2| + |2.5 - 3| = .5 + .5 = 1 and the answer to the question is YES

Next, let's choose a different value in that range...
IF... X = 2.4
|2.4 - 2| + |2.4 - 3| = .4 + .6 = 1 and the answer to the question is YES

That's interesting! Two different values of X produced the exact same answer. Let's try one more...
IF... X = 2.99
|2.99 - 2| + |2.99 - 3| = .99 + .1 = 1 and the answer to the question is YES

It certainly appears that the answer to the question is ALWAYS YES.
Fact 1 is SUFFICIENT

2) X > 2

With this Fact, we can use ANY of our prior examples from Fact 1:

IF... X = 2.5
|2.5 - 2| + |2.5 - 3| = .5 + .5 = 1 and the answer to the question is YES

But what if we TEST a value that is greater than 3?
IF... X = 4
|4 - 2| + |4 - 3| = 2 + 1 = 3 and the answer to the question is NO.
Fact 2 is INSUFFICIENT

Final Answer: A

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3008
Joined: Mon Aug 22, 2016 6:19 am
Location: Grand Central / New York
Thanked: 470 times
Followed by:34 members

by Jay@ManhattanReview » Mon Dec 12, 2016 1:01 am
fambrini wrote:If y = |x - 2| + |x - 3|, is y = 1?

1) 2 < x < 3

2) x > 2

OA: A
Let us take statement 1. Assume that x = 2, we get y = |2 - 2| + |2 - 3| = 1. Now assume that x = 3, we get y = |3 - 2| + |3 - 3| = 1. We see that value of y remains constant = 1 for a linear equation (y = |x - 2| + |x - 3|) whether x = 2 or x = 3, thus it would also render the same value of y = 1, if 2 < x < 3. Statement 1 is sufficient.

Statement 2 is not sufficient as for 2 < x < 3, we get y = 1, but y > 1 for x > 3. Say x = 4, then y = 3. Not sufficient.

Hope this helps!

-Jay

_________________
Manhattan Review GMAT Prep

Locations: New York | Mumbai | Ho Chi Minh City | Budapest | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.