If the integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of a^n, what is the value of a?
(1) a^n = 64
(2) n = 6
OA:B
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If the integers a and n are greater
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8! = 8*7*6*5*4*3*2 = (2³)(7)(2*3)(5)(2²)(3)(2) = (2�)(3)(5)(7).NandishSS wrote:If the integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of a^n, what is the value of a?
(1) a^n = 64
(2) n = 6
Since the product above is a multiple of a^n, we get:
(2�)(3)(5)(7) = (a^n)(k), where k is a positive integer.
Statement 1:
It's possible that a=2, n=6 and k=2*3*5*7, with the result that the following values in red are equal:
(2�)(3)(5)(7) = (2�)(2)(3)(5)(7)
It's possible that a=4, n=3 and k=2*3*5*7, with the result that the following values in blue are equal:
(2�)(3)(5)(7) = (4³)(2)(3)(5)(7).
Since a can be different values, INSUFFICIENT.
Statement 2:
(2�)(3)(5)(7) = (a�)(k).
The equation above is valid only if a=2 and k=2*3*5*7, as follows:
(2�)(3)(5)(7) = (2�)(2)(3)(5)(7).
Thus, a=2.
SUFFICIENT.
The correct answer is B.
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For the red colored part, how did it strike to you that you have to split it?Statement 1:
It's possible that a=2, n=6 and k=2*3*5*7, with the result that the following values in red are equal:
(2�)(3)(5)(7) = (2�)(2)(3)(5)(7)
It's possible that a=4, n=3 and k=2*3*5*7, with the result that the following values in blue are equal:
(2�)(3)(5)(7) = (4³)(2)(3)(5)(7).
Since a can be different values, INSUFFICIENT.
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Follow the portions in red and blue.sampatr wrote:For the red colored part, how did it strike to you that you have to split it?Statement 1:
It's possible that a=2, n=6 and k=2*3*5*7, with the result that the following values in red are equal:
(2�)(3)(5)(7) = (2�)(2)(3)(5)(7)
It's possible that a=4, n=3 and k=2*3*5*7, with the result that the following values in blue are equal:
(2�)(3)(5)(7) = (4³)(2)(3)(5)(7).
Since a can be different values, INSUFFICIENT.
Statement 1: a^n = 64
(2�)(3)(5)(7) = (a^n)(k).
(64*2)(3)(5)(7) = (a^n)(k).
Thus:
64 = a^n.
2*3*5*7 = k.
Statement 2: n=6
(2�)(3)(5)(7) = (a�)(k).
(2�*2)(3)(5)(7) = (a�)(k).
Thus:
2� = a�.
2*3*5*7 = k.
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We are given that integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of a^n, thus:NandishSS wrote:If the integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of a^n, what is the value of a?
(1) a^n = 64
(2) n = 6
8!/a^n = integer
Recall that 8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = (2^7) x (3^2) x 5 x 7.
We must determine the value of a.
Statement One Alone:
a^n = 64
There are multiple possible values of a. For instance, a = 2 and n = 6 (since 2^6 = 64) or a = 4 and n = 3 (since 4^3 = 64). Statement one alone is not sufficient to answer the question. We can eliminate answer choices A and D.
Statement Two Alone:
n = 6
Since n = 6, we know the following:
8!/a^6 = integer
The only factor in the prime factorization of 8! that has a power greater than 6 is 2^7; thus, the only possible value of a that will allow for 8!/a^6 to be an integer is 2.
Answer:B
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