Milk %
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- MartyMurray
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The first thing I noticed was that if z = 0, then you can just have even amounts of 1 percent and 2 percent grade, to get a 1.5 percent mixture. For instance, if x = 2 and y = 2, you get 4 gallons of 1.5 percent grade.750+ wrote:Three grades of milk are 1 percent, 2 percent and 3 percent fat by volume. If x gallons of the 1 percent grade, y gallons of the 2 percent grade, and z gallons of the 3 percent grade are mixed to give x + y + z gallons of a 1.5 percent grade, what is x in terms of y and z?
A. y + 3z
B. (y + z)/4
C. 2y + 3z
D. 3y + z
E. 3y + 4.5z
Similarly, you can set y = 0. Then to get a 1.5 percent mixture you need enough 1 percent with every gallon of 3 percent to get a weighted average of 1.5 percent. Since 1.5 is closer to 1 than to 3, x has to be greater than z.
If x > z then choices B and D are out.
If x and y are equal, actually the only answer that works is A.
So that's one hacking way to quickly get to the answer.
Alternatively, you could use the mixture formula, just using it with three components rather than the usual two.
1x + 2y + 3z = 1.5(x + y + z)
1x + 2y + 3z = 1.5x + 1.5y + 1.5z
.5y + 1.5z = .5x
y + 3z = x
The correct answer is A.
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- Brent@GMATPrepNow
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Let's start with a "word equation" and slowly turn it into an algebraic expression:Three grades of milk: 1%, 2%, and 3% fat by volume. X gallons of 1%, y gallons of 2%, and z gallons of 3% are mixed to give x + y + z gallons of 1.5%. What is x in terms of y and z?
a. y + 3z
b. (y + z)/4
c. 2y + 3z
d. 3y + z
e. 3y + 4z
Total fat in mixture = 1.5% of (x+y+z)
(1% of x) + (2% of y) + (3% of z) = 0.015(x+y+z)
Rewrite as: 0.01x + 0.02y + 0.03z = 0.015x + 0.015y + 0.015z
Multiply both sides by 100: 1x + 2y + 3z = 1.5x + 1.5y + 1.5z
Rearrange and simplify: 0.5y + 1.5z = 0.5x
Multiply both sides by 2 to get: y + 3z = x
Answer = A
Cheers,
Brent
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I posted two solutions here:
https://www.beatthegmat.com/gmat-practic ... 91092.html
https://www.beatthegmat.com/gmat-practic ... 91092.html
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As a tutor, I don't simply teach you how I would approach problems.
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Nice. I like that setting z to 0 approach. Not too often you can knock out four answer choices with a simple trick like that!Marty Murray wrote:The first thing I noticed was that if z = 0, then you can just have even amounts of 1 percent and 2 percent grade, to get a 1.5 percent mixture. For instance, if x = 2 and y = 2, you get 4 gallons of 1.5 percent grade.750+ wrote:Three grades of milk are 1 percent, 2 percent and 3 percent fat by volume. If x gallons of the 1 percent grade, y gallons of the 2 percent grade, and z gallons of the 3 percent grade are mixed to give x + y + z gallons of a 1.5 percent grade, what is x in terms of y and z?
A. y + 3z
B. (y + z)/4
C. 2y + 3z
D. 3y + z
E. 3y + 4.5z
Similarly, you can set y = 0. Then to get a 1.5 percent mixture you need enough 1 percent with every gallon of 3 percent to get a weighted average of 1.5 percent. Since 1.5 is closer to 1 than to 3, x has to be greater than z.
If x > z then choices B and D are out.
If x and y are equal, actually the only answer that works is A.
So that's one hacking way to quickly get to the answer.
Alternatively, you could use the mixture formula, just using it with three components rather than the usual two.
1x + 2y + 3z = 1.5(x + y + z)
1x + 2y + 3z = 1.5x + 1.5y + 1.5z
.5y + 1.5z = .5x
y + 3z = x
The correct answer is A.
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Hi 750+,
This is an "in terms of" question; these questions are usually built around 4-5 algebra steps and are fairly straight-forward "math" questions.
First, translate the equation:
[(.01x) + (.02y) + (.03z)] / {x + y + z] = .015
.01x + .02y + .03z = .015x + .015y + .015z
Let's multiply everything by 1000 to get rid of the decimals....
10x + 20y + 30z = 15x + 15y + 15z
5y + 15z = 5x
y + 3z = x
Final Answer: A
GMAT assassins aren't born, they're made,
Rich
This is an "in terms of" question; these questions are usually built around 4-5 algebra steps and are fairly straight-forward "math" questions.
First, translate the equation:
[(.01x) + (.02y) + (.03z)] / {x + y + z] = .015
.01x + .02y + .03z = .015x + .015y + .015z
Let's multiply everything by 1000 to get rid of the decimals....
10x + 20y + 30z = 15x + 15y + 15z
5y + 15z = 5x
y + 3z = x
Final Answer: A
GMAT assassins aren't born, they're made,
Rich