Is x-intercept of y=ax+b greater than 0?

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Is x-intercept of y=ax+b greater than 0?
1) ab<0
2) a+b<0

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by Brent@GMATPrepNow » Sun Jun 12, 2016 9:15 am
Max@Math Revolution wrote:Is x-intercept of y=ax+b greater than 0?

1) ab < 0
2) a+b<0
Target question: Is x-intercept POSITIVE?
The x-intercept is the x-value that satisfies the equation of the line when y = 0
So, we take y = ax + b and let y = 0 to get: 0 = ax + b
Subtract b from both sides to get: -b = ax
Divide both sides by a to get: -b/a = x
So, the x-intercept will be -b/a
This means we can REPHRASE the target question as ....
REPHRASED target question: Is -b/a POSITIVE?

Aside: We have a video with tips on rephrasing the target question: https://www.gmatprepnow.com/module/gmat- ... cy?id=1100

Statement 1: ab < 0 (in other words, ab is NEGATIVE)
This information is sufficient to answer the REPHRASED target question.
If the product ab is NEGATIVE, then we know that one value is positive and one is negative.
This tells us that b/a is also NEGATIVE, which means -b/a is POSITIVE
Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT

Statement 2: a+b<0
There are several values of a and b that satisfy statement 2. Here are two:
Case a: a = -1 and b = -1. In this case -b/a = -1. In other words, -b/a is NEGATIVE
Case b: a = 1 and b = -2. In this case -b/a = 2. In other words, -b/a is POSITIVE
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer = A

Related Video
x- and y- intercepts: https://www.gmatprepnow.com/module/gmat ... /video/996

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Max@Math Revolution » Mon Jun 13, 2016 8:48 am
If we modify the original condition and the question, the question becomes x-integercept=-b/a>0?, b/a<0?. If we multiply a^2, since it is a positive number, the sign of inequality does not change. Hence, it becomes ab>0?. So, since the condition 1) states ab<0, the answer is yes and the condition is sufficient. Hence, the correct answer is A.


- Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.