At the rate of m meters per s seconds, how many meters does a cyclist travel in x minutes?
A) m/sx
B) mx/s
C) 60m/sx
D) 60ms/x
E) 60mx/s
meters in x minutes
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One approach is to plug in values. Another is algebra. My preferred approach is to setup direct proportions. since the rate does not change, and rate is distance/time, we can write d1/t1 = d2/t2 where the distances are m and d, and the times are s seconds and x minutes (60x seconds). We're looking for "how many meters", the second distance.
Setup: m/s = d/60x and solve for d => d = 60mx/s. The full solution below is taken from the GMATFix App.
-Patrick
Setup: m/s = d/60x and solve for d => d = 60mx/s. The full solution below is taken from the GMATFix App.
-Patrick
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Here's the INPUT-OUTPUT approach.LulaBrazilia wrote:At the rate of m meters per s seconds, how many meters does a cyclist travel in x minutes?
A) m/sx
B) mx/s
C) 60m/sx
D) 60ms/x
E) 60mx/s
Choose some values that work for m, s and x.
If m = 1 and s = 60, we are saying that the cyclist travels at 1 meter per 60 seconds, which is the same as 1 mile per minute.
Now, let's say the cyclist wants to travel 2 miles (i.e., x = 2)
At a speed of 1 mile per minute, it will take the cyclist 2 minutes to travel 2 miles.
So, when the INPUT is m = 1, s = 60 and x = 2, the OUTPUT is 2 minutes
Now, we'll plug m = 1, s = 60 and x = 2 into the answer choices and see which one(s) yields an output of 2
A) m/sx = (1)/(60)(2) = 1/120 Nope
B) mx/s = (1)(2)/(60) = 1/30 Nope
C) 60m/sx = 60(1)/(60)(2) = 1/2 Nope
D) 60ms/x = 60(1)(60)/(2) = 1800 Nope
E) 60mx/s = 60(1)(2)/(60) = 2 PERFECT!
Answer: E
Cheers,
Brent
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Distance=Speed*time
question stem says rate or speed is m meters per s seconds ie m/s (per means divide by)
time =x minutes, convert it into seconds=60x
now plug in
d=m/s*60x=60mx/s
I believe this is not a 650+ question but somewhere around 350 to 400 kind of a range.
question stem says rate or speed is m meters per s seconds ie m/s (per means divide by)
time =x minutes, convert it into seconds=60x
now plug in
d=m/s*60x=60mx/s
I believe this is not a 650+ question but somewhere around 350 to 400 kind of a range.