If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ?
a 0.35 b 3.5 c. 35 d. 350 e. 3500
My approach:
1.25J=0.25K => K=5J
1.5K=0.5l => l=3K
0.75m=1.75l => m=(7/3)l
0.2m=2j*x; X=?
2j*x= 0.2m
2j*x= 0.2*(7/3)l
2j*x= 0.2*(7/3)*3k
2j*x= 0.2*7*5j
x=.1*7
%x=70%
Where am I going wrong?
OA: D
Percentage
You went wrong from .2m x =2j *x :hai1 wrote:If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ?
a 0.35 b 3.5 c. 35 d. 350 e. 3500
My approach:
1.25J=0.25K => K=5J
1.5K=0.5l => l=3K
0.75m=1.75l => m=(7/3)l
0.2m=2j*x; X=?
2j*x= 0.2m
2j*x= 0.2*(7/3)l
2j*x= 0.2*(7/3)*3k
2j*x= 0.2*7*5j
x=.1*7
%x=70%
Where am I going wrong?
OA: D
You should have had .2m = x% 2j
This gives
X= 10M/J
We know L= 3M/7 so 3m/7= 3K or K= m/7
K = 5J
m/7 = 5J
J= m/35
X= 10m/m/35 or 10m x 35/m = 350
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hai1 wrote:If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ?
a 0.35 b 3.5 c. 35 d. 350 e. 3500
My approach:
1.25J=0.25K => K=5J
1.5K=0.5l => l=3K
0.75m=1.75l => m=(7/3)l
0.2m=2j*x; X=?
2j*x= 0.2m
2j*x= 0.2*(7/3)l
2j*x= 0.2*(7/3)*3k
2j*x= 0.2*7*5j------->x=7/2=3.5=350%
x=.1*7------->cal mistake
%x=70%
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this is a great example for Pick The Value type question:
If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j
Lets say J = 100
25% K = 125% of 100
==> K = 125 * 100/25 = 500
150% of K = 50% L
==> 750 = 50%L
==> L = 1500
175% L = 75% M
==> 1.75 * 1500 = 75% M
==> M = 1500 * 1.75 * 100 / 75
==> M = 3500
20% M = 700
200% J = 200
Answer = (700 / 200) * 100 = 350%
Hence D
If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j
Lets say J = 100
25% K = 125% of 100
==> K = 125 * 100/25 = 500
150% of K = 50% L
==> 750 = 50%L
==> L = 1500
175% L = 75% M
==> 1.75 * 1500 = 75% M
==> M = 1500 * 1.75 * 100 / 75
==> M = 3500
20% M = 700
200% J = 200
Answer = (700 / 200) * 100 = 350%
Hence D
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all percentage is translated into decimals - multiply the answer by 100
5j/4=k/4 <> 5j=k
3k/2=l/2 <> 3k=l
7l/4=3m/4 <> 7l=3m ..................................................75%=3/4;175%=1 3/4
find x from `` m/5=x*2j <> m=x*10j
10j=2k --> 2k=2l/3 --> 2l/3=3m/7 *2/3=2m/7 Thus 10j=2m/7 substitute into m=x*10j --> m=x*2m/7 --> x=7m/2m, x=3.5
3.5*100=350% (answer D)
5j/4=k/4 <> 5j=k
3k/2=l/2 <> 3k=l
7l/4=3m/4 <> 7l=3m ..................................................75%=3/4;175%=1 3/4
find x from `` m/5=x*2j <> m=x*10j
10j=2k --> 2k=2l/3 --> 2l/3=3m/7 *2/3=2m/7 Thus 10j=2m/7 substitute into m=x*10j --> m=x*2m/7 --> x=7m/2m, x=3.5
3.5*100=350% (answer D)
hai1 wrote:If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ?
a 0.35 b 3.5 c. 35 d. 350 e. 3500
My approach:
1.25J=0.25K => K=5J
1.5K=0.5l => l=3K
0.75m=1.75l => m=(7/3)l
0.2m=2j*x; X=?
2j*x= 0.2m
2j*x= 0.2*(7/3)l
2j*x= 0.2*(7/3)*3k
2j*x= 0.2*7*5j --> x=0.1*7*5 (inaccurate calc.)
x=.1*7*5
%x=(70*5)%
Where am I going wrong?
OA: D
Hi,
Can anyone help with the method i tried below.
From the given data, i formed the ratios
J/K = 1/5 , K/L = 1/3 ,L/M = 3/7.
Inorder to relate J and M, i made the intermediates to be in common terms.
J/K = 1/5 , K/L = 5/15, L/M = 15/105.
I presumed , Now when J=1, M = 105. But these values
when substitued in the eqn
0.2M = 2.0 * J * X is not working.
Kindly help
Can anyone help with the method i tried below.
From the given data, i formed the ratios
J/K = 1/5 , K/L = 1/3 ,L/M = 3/7.
Inorder to relate J and M, i made the intermediates to be in common terms.
J/K = 1/5 , K/L = 5/15, L/M = 15/105.
I presumed , Now when J=1, M = 105. But these values
when substitued in the eqn
0.2M = 2.0 * J * X is not working.
Kindly help
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jaguar123 wrote:Hi,
Can anyone help with the method i tried below.
From the given data, i formed the ratios
J/K = 1/5 , K/L = 1/3 ,L/M = 3/7.
From the question, 7L/8=3M/4. So, L/M=6/7
Answer is D.
My way of solving this is to reduce the general case into a specific case (sorry, algebra!)
Let:
j = 4
Which gives:
k = 20
l = 60
m = 140
0.2m = 28
2j = 8
0.2m/2j = 28/8 = 3.5 = 350% (question asks for percent)
Easy-peasy : )
My way of solving this is to reduce the general case into a specific case (sorry, algebra!)
Let:
j = 4
Which gives:
k = 20
l = 60
m = 140
0.2m = 28
2j = 8
0.2m/2j = 28/8 = 3.5 = 350% (question asks for percent)
Easy-peasy : )
If you found one of my answers useful, hit the shiny Thanks button! : )
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125% of j is equal to 25% of khai1 wrote:If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ?
a 0.35 b 3.5 c. 35 d. 350 e. 3500
My approach:
1.25J=0.25K => K=5J
1.5K=0.5l => l=3K
0.75m=1.75l => m=(7/3)l
0.2m=2j*x; X=?
2j*x= 0.2m
2j*x= 0.2*(7/3)l
2j*x= 0.2*(7/3)*3k
2j*x= 0.2*7*5j
x=.1*7
%x=70%
Where am I going wrong?
OA: D
750% of j is equal to 150% of k
150% of k is equal to 50% of l
750% of J is equal to 50% of l
2625% of j is equal to 175% of l
2625% of j is equal to 75% of m
Therefore,20% of m is (2625/75 )*20= x % of 200% of J
Ans :350
Hi MM_Ed,MM_Ed wrote:Answer is D.
My way of solving this is to reduce the general case into a specific case (sorry, algebra!)
Let:
j = 4
Which gives:
k = 20
l = 60
m = 140
0.2m = 28
2j = 8
0.2m/2j = 28/8 = 3.5 = 350% (question asks for percent)
Easy-peasy : )
Can you please suggest what made you choose 4 for J? Thanks.
The questions mentions 25% and 125%, so I went for 4 (25% of 4 = 1) for convenience : )bharti06 wrote:Hi MM_Ed,MM_Ed wrote:Answer is D.
My way of solving this is to reduce the general case into a specific case (sorry, algebra!)
Let:
j = 4
Which gives:
k = 20
l = 60
m = 140
0.2m = 28
2j = 8
0.2m/2j = 28/8 = 3.5 = 350% (question asks for percent)
Easy-peasy : )
Can you please suggest what made you choose 4 for J? Thanks.
If you found one of my answers useful, hit the shiny Thanks button! : )