Each term in the sequence A1 +A2 + A3 ----- + An is either 7 or 77 and th sum equals 350. What could be the value of n.
a) 38
b) 39
c) 40
d) 41
e) 42
each term equal to 7 or 77
This topic has expert replies
-
- Senior | Next Rank: 100 Posts
- Posts: 37
- Joined: Mon Jul 06, 2015 2:46 am
- DavidG@VeritasPrep
- Legendary Member
- Posts: 2663
- Joined: Wed Jan 14, 2015 8:25 am
- Location: Boston, MA
- Thanked: 1153 times
- Followed by:128 members
- GMAT Score:770
Let's take the simplest possible scenario. Imagine that every term in the sequence were 7. How many of those would we need for the sum to be 350? We'd need 50. Not an answer choice, but it is in the ballpark.Each term in the sequence A1 +A2 + A3 ----- + An is either 7 or 77 and th sum equals 350. What could be the value of n.
a) 38
b) 39
c) 40
d) 41
e) 42
Say, then that we had one 77. We'd need the 7's to sum to 273. (350 - 77 = 273) There are thirty-nine 7's in 273. If we have one 77 and and thirty-nine 7's, we'll have a total of 1 + 39 = 40 terms. Answer is C
- DavidG@VeritasPrep
- Legendary Member
- Posts: 2663
- Joined: Wed Jan 14, 2015 8:25 am
- Location: Boston, MA
- Thanked: 1153 times
- Followed by:128 members
- GMAT Score:770
One alternative: use the units digits. Both 77 and 7 end in 7. We know that the sum should be 350, which ends in 0. Now use the answer choices.Each term in the sequence A1 +A2 + A3 ----- + An is either 7 or 77 and th sum equals 350. What could be the value of n.
a) 38
b) 39
c) 40
d) 41
e) 42
A) If we had 38 terms all ending in 7, the units digit would be 6. (8*7 = 56, and 56 ends in 6.) No good. 350 ends in 0.
B) If we had 39 terms all ending in 7, the units digit would be 3. (9*7 = 63, and 63 ends in 3.) No good
C) If we had 40 terms all ending in 7, the units digit would be 0. (0*7 = 0) 350 ends in 0, so we've got our answer.
-
- Senior | Next Rank: 100 Posts
- Posts: 37
- Joined: Mon Jul 06, 2015 2:46 am
GMAT/MBA Expert
- [email protected]
- Elite Legendary Member
- Posts: 10392
- Joined: Sun Jun 23, 2013 6:38 pm
- Location: Palo Alto, CA
- Thanked: 2867 times
- Followed by:511 members
- GMAT Score:800
Hi rakaisraka,
Here is one of the discussions on this particular prompt:
https://www.beatthegmat.com/lucky-again- ... 75428.html
GMAT assassins aren't born, they're made,
Rich
Here is one of the discussions on this particular prompt:
https://www.beatthegmat.com/lucky-again- ... 75428.html
GMAT assassins aren't born, they're made,
Rich
- Max@Math Revolution
- Elite Legendary Member
- Posts: 3991
- Joined: Fri Jul 24, 2015 2:28 am
- Location: Las Vegas, USA
- Thanked: 19 times
- Followed by:37 members
Each term in the sequence A1 +A2 + A3 ----- + An is either 7 or 77 and th sum equals 350. What could be the value of n.
a) 38
b) 39
c) 40
d) 41
e) 42
Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.
==> 350=7*50=7+7+....+7 (the number of 7s is 50), 77=7*11=7+7+...+7 (the number of 7s is 11)
so,
350=7*50 ==> n=50
350=7*39+7*11=7*39+77*1 ==> n=40=39+1
350=7*28+7*22=7*28+77*2 ==> n=30=28+2
50, 40, 30 coule be the value of n
Therefore, the answer is C.
www.mathrevolution.com
- The one-and-only World's First Variable Approach for DS and IVY Approach for PS that allow anyone to easily solve GMAT math questions.
- The easy-to-use solutions. Math skills are totally irrelevant. Forget conventional ways of solving math questions.
- The most effective time management for GMAT math to date allowing you to solve 37 questions with 10 minutes to spare
- Hitting a score of 45 is very easy and points and 49-51 is also doable.
- Unlimited Access to over 120 free video lessons at https://www.mathrevolution.com/gmat/lesson
- Our advertising video at https://www.youtube.com/watch?v=R_Fki3_2vO8
a) 38
b) 39
c) 40
d) 41
e) 42
Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.
==> 350=7*50=7+7+....+7 (the number of 7s is 50), 77=7*11=7+7+...+7 (the number of 7s is 11)
so,
350=7*50 ==> n=50
350=7*39+7*11=7*39+77*1 ==> n=40=39+1
350=7*28+7*22=7*28+77*2 ==> n=30=28+2
50, 40, 30 coule be the value of n
Therefore, the answer is C.
www.mathrevolution.com
- The one-and-only World's First Variable Approach for DS and IVY Approach for PS that allow anyone to easily solve GMAT math questions.
- The easy-to-use solutions. Math skills are totally irrelevant. Forget conventional ways of solving math questions.
- The most effective time management for GMAT math to date allowing you to solve 37 questions with 10 minutes to spare
- Hitting a score of 45 is very easy and points and 49-51 is also doable.
- Unlimited Access to over 120 free video lessons at https://www.mathrevolution.com/gmat/lesson
- Our advertising video at https://www.youtube.com/watch?v=R_Fki3_2vO8
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
The above solutions are faster. However, if you didn't spot them, another approach is to look for a pattern.rakaisraka wrote:Each term in the sequence A1 +A2 + A3 ----- + An is either 7 or 77 and th sum equals 350. What could be the value of n.
a) 38
b) 39
c) 40
d) 41
e) 42
The sum of any 1 term will have units digit 7
The sum of any 2 terms will have units digit 4
The sum of any 3 terms will have units digit 1
The sum of any 4 terms will have units digit 8
The sum of any 5 terms will have units digit 5
The sum of any 6 terms will have units digit 2
The sum of any 7 terms will have units digit 9
The sum of any 8 terms will have units digit 6
The sum of any 9 terms will have units digit 3
The sum of any 10 terms will have units digit 0
The sum of any 11 terms will have units digit 7 (at this point, the pattern repeats)
From this, we can conclude that the sum of any 20 terms will have units digit 0
And the sum of any 30 terms will have units digit 0, and so on.
We are told the sum of the terms is 350 (units digit 0), so the number of terms must be 10 or 20 or 30 or . . .
Since C is a multiple of 10, this must be the correct answer.
Cheers,
Brent