This is how Edward's lotteries work. First 9 different numbers are selected. tickets with exactly 6 of the nine numbers randomly selected and printed such that no two tickets have the same set of numbers. Finally, the winning ticket is the one containing the 6 numbers drawn from the 9 randomly. There is exactly one winning ticket in the lottery system. How many tickets can the lottery system print?
1) 9p6
2) 9p3
3) 9c9
4) 9c6
5) 6^9
Lottery
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Hi nahid078,
What is the source of this question? I ask because it's poorly-worded and you would benefit by working with better material. There are plenty of study materials available that are more in-line with what you'll see on the Official GMAT.
GMAT assassins aren't born, they're made,
Rich
What is the source of this question? I ask because it's poorly-worded and you would benefit by working with better material. There are plenty of study materials available that are more in-line with what you'll see on the Official GMAT.
GMAT assassins aren't born, they're made,
Rich
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In addition to being poorly-worded, the question also has problems with the answer choices.
The test-makers don't expect you to know what 9P6 and 9C6 mean.
In fact, in its math syllabus, the OG uses a different notation for combinations.
Cheers,
Brent
The test-makers don't expect you to know what 9P6 and 9C6 mean.
In fact, in its math syllabus, the OG uses a different notation for combinations.
Cheers,
Brent
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Suppose we have two letters A and B. We can have 2 sets,
AB, and BA. According to the question, no two tickets have the same sets. This means that if I have a ticket that have the letters BA on it, then I cannot have a ticket AB. In other words,
the order does not matter.
In this question, I assume that there is a set of numbers 123456 on ticket 1. Any other combination cannot be on other tickets. 123465 for example cannot be on another ticket...
So the coreect answer is 9C6
AB, and BA. According to the question, no two tickets have the same sets. This means that if I have a ticket that have the letters BA on it, then I cannot have a ticket AB. In other words,
the order does not matter.
In this question, I assume that there is a set of numbers 123456 on ticket 1. Any other combination cannot be on other tickets. 123465 for example cannot be on another ticket...
So the coreect answer is 9C6
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Please provide reference in the Nova Math Bible book. I have the soft copy. Will check it there.