Please let me know if my approach looks correct

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The equation can be broken into three cases x> 3, x = 3, x < 3

Case 1. x > 3 => is x-3 = 3-x? NO
Case 2. x < 3 => is -(x-3) = 3-x ? YES
Case 3. x= 3 is |x-3| = 3-x ? YES

From Statement 1=> x is not equal to 3. So it can be > 3 or < 3 => NOT SUFFICIENT

From (2) => -x|x| > 0
solving, for x > 0 => -x^2 > 0 => NOT POSSIBLE as x^2 is positive and negating it will be < 0.
for x < 0 => -x(-x) > 0 => x^2 > 0 => TRUE so x < 0 and hence x < 3.
Statement 2 is SUFFICIENT.

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by [email protected] » Wed Oct 01, 2014 10:46 pm
Hi practhi18oct,

Yes, your approach is correct. This DS question has a clever "design element" to it - the entire prompt revolves around X and it's relationship to the number 3 (less than 3, equal to 3, greater than 3). Recognizing the built-in patterns that the GMAT writers place into their questions can make answering those questions a whole lot easier.

In other DS prompts, you might have to do a bit more work and consider other possibilities (e.g. X as a positive or negative fraction), but you nailed it here. As you continue to practice DS questions, it's important to be thorough - there are always obvious possibilities, but the measure of your success with be in spotting and evaluating the LESS OBVIOUS possibilities.

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by Brent@GMATPrepNow » Thu Oct 02, 2014 2:17 am
Is √[(x - 3)²] = 3 - x ?

1. x ≠ 3
2. -x|x| > 0
Target question: Is √[(x - 3)²] = 3 - x ?

This question is a great candidate for rephrasing the target question.
Aside: We have a free video with tips on rephrasing the target question: https://www.gmatprepnow.com/module/gmat- ... cy?id=1100

To begin, notice that we have two nice rules:
- If k > 0, then √(k²) = k
- If k < 0, then √(k²) = -k


Now observe that (3-x) = -(x-3)

Given the above information, under what conditions will √[(x-3)²] = 3-x?
In other words, under what conditions will √[(x-3)²] = -(x-3)?
This will occur IF x-3 is NEGATIVE.

So, we can now rephrase the target question as: Is (x-3) negative?
Or we can write: Is x-3 < 0?

. . . or better yet: Is x < 3?

Now that we've REPHRASED the target question in much simpler terms, we can check the statements.

Statement 1: x ≠ 3
This does not give us a definitive answer to the REPHRASED target question (Is x < 3? )
As such, statement 1 is NOT SUFFICIENT

Statement 2: -x|x| > 0
First notice that this implies that x does not equal zero.
Next, notice that, if x does not equal zero, then |x| will always be positive.
So, -x|x| > 0 is the same as saying (-x)(positive) > 0
In other words, the product (-x)(positive) results in a positive number.
This tells us that (-x) must be positive, which means x must be negative.
If x is negative, then x is definitely less than 3.
Since we can answer the REPHRASED target question with certainty, statement 2 is SUFFICIENT

Answer = B

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by GMATGuruNY » Thu Oct 02, 2014 2:29 am
Is √[(x - 3)²] = 3 - x ?

1. x ≠ 3
2. -x|x| > 0
Be definition:
√(x²) = |x|.
|x-y| is the DISTANCE between x and y.

Question rephrased: Is |x-3| = 3-x?
In other words:
Is the DISTANCE between x and 3 equal to the DIFFERENCE between 3 and x?

A DIFFERENCE can be negative, 0, or positive.
A DISTANCE must be greater than or equal to 0.
For the DIFFERENCE between two values to be equal to the DISTANCE between the two values, the DIFFERENCE -- like the DISTANCE -- must be greater than or equal to 0:
3-x≥0
x≤3.

Question rephrased: Is x≤3?

Statement 1: x is not equal to 3.
It is possible that x<3 or that x>3.
INSUFFICIENT.

Statement 2: -x|x| > 0 .
Thus, the left-hand side must be (+)(+) or (-)(-).
Since |x| cannot be negative, both factors on the left-hand side must be positive.
Thus:
-x>0
x<0.
Since x<0, we know that x≤3.
SUFFICIENT.

The correct answer is B.
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