If a jury of 12 people is to be selected randomly from a pool of 15 potential jurors, and the jury pool consists of 2/3 men and 1/3 women, what is the probability that the jury will comprise at least 2/3 men?
A)24/91
B)45/91
C)2/3
D)67/91
E)84/91
OAD
Jury
This topic has expert replies
-
- Legendary Member
- Posts: 510
- Joined: Thu Aug 07, 2014 2:24 am
- Thanked: 3 times
- Followed by:5 members
- GMATGuruNY
- GMAT Instructor
- Posts: 15539
- Joined: Tue May 25, 2010 12:04 pm
- Location: New York, NY
- Thanked: 13060 times
- Followed by:1906 members
- GMAT Score:790
Question rephrased: What is the probability that at least 8 men will be selected to serve on the 12-member jury?j_shreyans wrote:If a jury of 12 people is to be selected randomly from a pool of 15 potential jurors, and the jury pool consists of 2/3 men and 1/3 women, what is the probability that the jury will comprise at least 2/3 men?
A) 24/91
B) 45/91
C) 2/3
D) 67/91
E) 84/91
P(good outcome) = 1 - P(bad outcome).
Here, a BAD outcome means selecting a jury with FEWER than 8 men.
Of the 10 men and 5 women in the jury pool, 3 people must be selected NOT to serve on the jury.
There is only ONE WAY to select fewer than 8 men FOR the jury:
The 3 people selected NOT to serve on the jury must ALL be men, leaving 7 men and all 5 women to serve on the jury.
P(1st non-juror is a man) = 10/15. (Of the 15 people in the jury pool, 10 are men.)
P(2nd non-juror is a man) = 9/14. (Of the 14 remaining people in the jury pool, 9 are men.)
P(3rd non-juror is a man) = 8/13. (Of the 13 remaining people in the jury pool, 8 are men.)
Since a bad outcome requires that all 3 events happen, we MULTIPLY the fractions:
10/15 * 9/14 * 8/13 = 24/91.
Thus:
P(good outcome) = 1 - 24/91 = 67/91.
The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Hi GMATGuru,
Cant we attempt this question by selecting like:
Probability of selecting (8M & 4W) + Prob. (9M & 3W) + Prob. (10M & 2W)!!
Please explain!
Thanks.
Cant we attempt this question by selecting like:
Probability of selecting (8M & 4W) + Prob. (9M & 3W) + Prob. (10M & 2W)!!
Please explain!
Thanks.
GMATGuruNY wrote:Question rephrased: What is the probability that at least 8 men will be selected to serve on the 12-member jury?j_shreyans wrote:If a jury of 12 people is to be selected randomly from a pool of 15 potential jurors, and the jury pool consists of 2/3 men and 1/3 women, what is the probability that the jury will comprise at least 2/3 men?
A) 24/91
B) 45/91
C) 2/3
D) 67/91
E) 84/91
P(good outcome) = 1 - P(bad outcome).
Here, a BAD outcome means selecting a jury with FEWER than 8 men.
Of the 10 men and 5 women in the jury pool, 3 people must be selected NOT to serve on the jury.
There is only ONE WAY to select fewer than 8 men FOR the jury:
The 3 people selected NOT to serve on the jury must ALL be men, leaving 7 men and all 5 women to serve on the jury.
P(1st non-juror is a man) = 10/15. (Of the 15 people in the jury pool, 10 are men.)
P(2nd non-juror is a man) = 9/14. (Of the 14 remaining people in the jury pool, 9 are men.)
P(3rd non-juror is a man) = 8/13. (Of the 13 remaining people in the jury pool, 8 are men.)
Since a bad outcome requires that all 3 events happen, we MULTIPLY the fractions:
10/15 * 9/14 * 8/13 = 24/91.
Thus:
P(good outcome) = 1 - 24/91 = 67/91.
The correct answer is D.
GMAT/MBA Expert
- [email protected]
- Elite Legendary Member
- Posts: 10392
- Joined: Sun Jun 23, 2013 6:38 pm
- Location: Palo Alto, CA
- Thanked: 2867 times
- Followed by:511 members
- GMAT Score:800
Hi ProGMAT,
Yes, you CAN answer the question by solving the individual calculations that you listed. Here's how....
Since we're selecting 12 people from a group of 15, and the order doesn't matter, we can use the combination formula:
N!/[K!(N-K)!]
15c12 = 15!/[12!(3!)] = 455 possible groups of 12
Now we calculate each of the possible options that fits what we're looking for:
8 men (from 10) and 4 women (from 5) = (10c8)(5c4) = (45)(5) = 225
9 men (from 10) and 3 women (from 5) = (10c9)(5c3) = (10)(10) = 100
10 men (from 10) and 2 women (from 5) = (10c10)(5c2) = (1)(10) = 10
Total options with at least 8 men = 335
Probability = 335/455 = 67/91
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
Yes, you CAN answer the question by solving the individual calculations that you listed. Here's how....
Since we're selecting 12 people from a group of 15, and the order doesn't matter, we can use the combination formula:
N!/[K!(N-K)!]
15c12 = 15!/[12!(3!)] = 455 possible groups of 12
Now we calculate each of the possible options that fits what we're looking for:
8 men (from 10) and 4 women (from 5) = (10c8)(5c4) = (45)(5) = 225
9 men (from 10) and 3 women (from 5) = (10c9)(5c3) = (10)(10) = 100
10 men (from 10) and 2 women (from 5) = (10c10)(5c2) = (1)(10) = 10
Total options with at least 8 men = 335
Probability = 335/455 = 67/91
Final Answer: D
GMAT assassins aren't born, they're made,
Rich