If k is an integer, and 35^2-1/k is an integer, then k could be each of the following, EXCEPT
(A) 8(B) 9(C) 12(D) 16(E) 17
If k is an integer
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Using the formula (x^2 - y^2 ) = (x+y)(x-y)
35^2 -1 = 35^2 - 1^2
We can write this as (35+1)(35-1)= 36 x 34
So the question becomes (36 x 34)/ k = int .
K is an integer .
so only number that can not divide completely is 8 .
[spoiler]Ans : A .[/spoiler]
whats the OA ?
35^2 -1 = 35^2 - 1^2
We can write this as (35+1)(35-1)= 36 x 34
So the question becomes (36 x 34)/ k = int .
K is an integer .
so only number that can not divide completely is 8 .
[spoiler]Ans : A .[/spoiler]
whats the OA ?
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- Rahul@gurome
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Given expression can be written as (35^2 - 1^2)/k = (35 - 1)(35 + 1)/k = (34)(36)/k
(34)(36)/k = (2^3)(3^2)(17)/k
From the given answer choices, k = 8, 9, 12, 17 will give (2^3)(3^2)(17)/k as an integer.
But k = 16 does not give an integer.
The correct answer is (D).
(34)(36)/k = (2^3)(3^2)(17)/k
From the given answer choices, k = 8, 9, 12, 17 will give (2^3)(3^2)(17)/k as an integer.
But k = 16 does not give an integer.
The correct answer is (D).
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jeez.I got confused and thought it was (35)^(2-1/k). I thought man its a crazy problem.After seeing how you approached the problem,I was relieved that it was a normal problem.
- sumit.sinha
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The expression is 35^2 - 1/k and NOT (35^2 - 1)/k. The actual question does not contain brackets.Mogorosi wrote:Hello guys,
is this expression 35^2 - 1/k or (35^2 - 1)/k?
So,
The Correct answer is (B) 9.
Cheers,
Sumit
Sumit
- anirudhbhalotia
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sumit.sinha wrote:The expression is 35^2 - 1/k and NOT (35^2 - 1)/k. The actual question does not contain brackets.Mogorosi wrote:Hello guys,
is this expression 35^2 - 1/k or (35^2 - 1)/k?
So,
The Correct answer is (B) 9.
So if the answer is B, can we have the steps to solve it in the most easy and efficient way.
Thanks!
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You are right but from the left only....not actuallysumit.sinha wrote: The expression is 35^2 - 1/k and NOT (35^2 - 1)/k. The actual question does not contain brackets.
So,
The Correct answer is (B) 9.
just kidding
see this
https://www.beatthegmat.com/35-2-1-k-is- ... 66222.html
any way if question was so i think it could be solved but may be options will have to be different then
but have not tried.
thanks
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@Sumit: I agree that the problem should not be (35^2-1)/K, but rather be 35^2 - 1/k. Please help me derive the answer to the later. I tried to solve it this way:
35^2-1/K ---> ((5x5x7x7xK)-1) /K
Now i can see that 5x5x7x7xK is a multiple of K and is therefore always divisible by K. But when you subtract 1 from it, it cannot be divisible by K. Thus for any integer value of K, i dont see that the overall expression will lead to an Integer.
Please help me. I guess i'm missing something here !!!!!
Cheers...
35^2-1/K ---> ((5x5x7x7xK)-1) /K
Now i can see that 5x5x7x7xK is a multiple of K and is therefore always divisible by K. But when you subtract 1 from it, it cannot be divisible by K. Thus for any integer value of K, i dont see that the overall expression will lead to an Integer.
Please help me. I guess i'm missing something here !!!!!
Cheers...
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Thank you, Ajayd, for confirming that I'm not losing my mind.
Somewhere in my distant past, I learned about "order of operations", such as multiplication and division taking precedence over addition and subtraction.
As expressed, 35^2 - 1/k = (35*35) - (1/k) = 1225 - (1/k)
If k=9, this would equal 1225 - 1/9 = 1224 + 8/9
Somewhere in my distant past, I learned about "order of operations", such as multiplication and division taking precedence over addition and subtraction.
As expressed, 35^2 - 1/k = (35*35) - (1/k) = 1225 - (1/k)
If k=9, this would equal 1225 - 1/9 = 1224 + 8/9
ajayd wrote:the question is wrong. it should be (35^2-1)/k
I'm really old, but I'll never be too old to become more educated.