Data sufficiency

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Data sufficiency

by vmahi7 » Mon Aug 18, 2014 8:56 pm
is |X+Y|>|X-Y|..?

a)|X|>|Y|
b)|X-Y|<|X|

i am very confused ....

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by GMATGuruNY » Mon Aug 18, 2014 9:31 pm
Is |x+y|>|x-y|?

a) |x|>|y|

b) |x-y|<|x|
Algebraic approach"

Is |x+y| > |x-y|?
When there is absolute value notation on each side, we can square the inequality.

(x+y)² > (x-y)²
x² + 2xy + y² > x² - 2xy + y²
4xy > 0
xy > 0.

Question rephrased: Do x and y have the same sign?

Statement 1: |x| > |y|
Here, x and y could have the same sign or different signs.
INSUFFICIENT.

Statement 2: |x-y| < |x|
Squaring both sides, we get:
(x-y)² < x²
x² - 2xy + y² < x²
y² < 2xy
xy > y²/2.
Since the square of a value cannot be negative, y²/2 cannot be negative.
Thus, xy>0, implying that x and y have the same sign.
SUFFICIENT.

The correct answer is B.

Number line approach:

|x-y| = the distance between x and y.
|x+y| = the distance between x and -y.
|x| = the distance between x and 0.

Is |x-y| < |x+y|?
In words:
Is the distance between between x and y less than the distance between x and -y?
For x to be CLOSER TO Y than to -y, x and y must be TO THE SAME SIDE OF 0.
To illustrate:
x.....y..............0.............-y
.......y.....x.......0.............-y
As these examples show, when x and y are to the same side of 0, x is closer to y than to -y.

Question rephrased: Are x and y to the same side of 0?

Statement 1: |x| > |y|
x and y could be to the same of 0 or to opposite sides of 0.
INSUFFICIENT.

Statement 2: |x-y| < |x|
In words:
The distance between x and y is less than the distance between x and 0.
This will not be true if x and y are to opposite sides of 0.
To illustrate:
x.........0...........y
y.........0..........x
In each case here, the distance between x and y is GREATER than the distance between x and 0.
Thus, to satisfy statement 2, x and y must be TO THE SAME SIDE OF 0.
SUFFICIENT.

The correct answer is B.
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by GMATinsight » Tue Aug 19, 2014 11:02 am
vmahi7 wrote:is |X+Y|>|X-Y|..?

a)|X|>|Y|
b)|X-Y|<|X|

i am very confused ....
ALTERNATE

Question : is |X+Y|>|X-Y|..?

But we must observe that |X+Y| will ONLY be greater than |X-Y| when the signs of X and Y are same. Therefore,

Question Rephrased : Do X and Y have Same Signs?

Statement 1) |X|>|Y|

This Inequation Doesn't help identify anything about the Signs of Variable as Modulus manipulates the Negative sign and keeps the positive sign as positive, therefore

INSUFFICIENT


Statement 2)|X-Y|<|X|

Which is Possible only when Signs of X and Y are SAME and X and Y are non-zero (You may try substituting positive and negative values of X and Y for your satisfaction, therefore

SUFFICIENT

Answer: Option B
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