If n and k are positive integers, is sqrt(n+k) > 2*sqrt(n)?
1) k > 3n
2) n+k > 3n
Is sqrt(n+k) > 2*sqrt(n)?
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This question tests your understanding that so long as you're dealing with positive values, x>y means that x^2 > y^2. So we can square each side and rephrase the question as: is n+k > 4n? --> is n>3k?
The answer is A. I go through the question in detail in the full solution below (taken from the GMATFix App).
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The answer is A. I go through the question in detail in the full solution below (taken from the GMATFix App).
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n & k = +ve
sqrt(n+k) > 2*sqrt(n)
Or,
n + k > 4n
TO FIND: k > 3n
Statement 1:
k > 3n
SUFFICIENT
Statement 2:
n + k > 3n
k > 2n
INSUFFICIENT
[spoiler]{A}[/spoiler]
sqrt(n+k) > 2*sqrt(n)
Or,
n + k > 4n
TO FIND: k > 3n
Statement 1:
k > 3n
SUFFICIENT
Statement 2:
n + k > 3n
k > 2n
INSUFFICIENT
[spoiler]{A}[/spoiler]
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