At what angle do lines y=Kx+B and y=Bx+K intersect ?
(1) B+K=1
(2) BK=0
Tough DS
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Q: Angle made by the linesrakeshd347 wrote:At what angle do lines y=Kx+B and y=Bx+K intersect ?
(1) B+K=1
(2) BK=0
y = Kx + B ... (i)
y = Bx + K ... (ii)
We need the values of K and B both to find the equations of the 2 lines.
St1:
B + K = 1
Many numbers satisfy this equation. B = 0, K = 1; B = 2, K = -1 ... Thus we dont have a definite answer for the Slope and the Intercept of the lines (i) & (ii)
INSUFFICIENT
St2:
BK = 0
We can have three cases here
1) B = 0; (i) becomes y = Kx (ii) becomes y = K (We still need the value of K)
2) K = 0; (i) becomes y = B (ii) becomes y = Bx (We still need the value of B)
3) B = K = 0; The two equations become the X Axis itself.
All the three cases are possible, So the statement is INSUFFICIENT
St1+St2:
Now we know that the sum must be equal to 1; Case 3 of st2 becomes invalid.
1) B = 0; K = 1 (Since B + K = 1); (i) becomes y = x (ii) becomes y = 1
1) K = 0; B = 1 (Since B + K = 1); (i) becomes y = 1 (ii) becomes y = x
The two equations are y = 1 & y = x and the angle made by them is 45.
SUFFICIENT.
Answer C
Regards,
Vivek
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I like this problem. What's the source?
Ron has been teaching various standardized tests for 20 years.
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Pueden hacerle preguntas a Ron en castellano
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Voit esittää kysymyksiä Ron:lle myös suomeksi
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Sorry forgot to mention the source. This problem is created by Bunuel from GMATCLUB it was in one of the gmatclub tests. Surely its not from OG or Official source.lunarpower wrote:I like this problem. What's the source?