In the xy-plane, point (r,s) lies on a circle with center at the origin. What is the value of r^2 + s^2?
1) The circle has a radius 2.
2) The point (sqrt2, -sqrt2) lies on the circle.
Would someone mind drawing a picture for this. I'm not understanding how to set up this problem.
Simple coordinate geometry Quant Review 2nd Ed #22
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Step 1: (Simplify):runningguy wrote:In the xy-plane, point (r,s) lies on a circle with center at the origin. What is the value of r^2 + s^2?
1) The circle has a radius 2.
2) The point (sqrt2, -sqrt2) lies on the circle.
Would someone mind drawing a picture for this. I'm not understanding how to set up this problem.
Consider the following diagram, (r,s) is on the circle and can be any where (depends on the value of r and s). However the question just asks us to find so essentially it is asking us to find the radius of the circle. Restated question => What is the radius of the circle?
Step 2: (Consider the statements 1 and 2)
St1: Gives the radius directly, SUFFICIENT
St2: Gives another point which is again on the circle, and thus by Pythagoras theorem
Thus, radius == 2
SUFFICIENT.
ANSWER is D
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Way too much work for statement 2.mevicks wrote:St2: Gives another point which is again on the circle, and thus by Pythagoras theorem
Thus, radius == 2
SUFFICIENT.
* You have the center (= the origin).
* You're given a specific point.
* So, you have the radius.
Done. Sufficient.
If you calculate anything for this statement, you're wasting your time -- and, more importantly, you're forgetting the goal of the problem!
The goal of DS problems is not to find answers. If you know that the answer can be found, that's enough.
Ron has been teaching various standardized tests for 20 years.
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Pueden hacerle preguntas a Ron en castellano
Potete chiedere domande a Ron in italiano
On peut poser des questions à Ron en français
Voit esittää kysymyksiä Ron:lle myös suomeksi
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Quand on se sent bien dans un vêtement, tout peut arriver. Un bon vêtement, c'est un passeport pour le bonheur.
Yves Saint-Laurent
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Learn more about ron