| View previous topic :: View next topic |
| Author |
Message |
dominate11 Just gettin' started!
Joined: 10 Jan 2007 Posts: 4
Thanks given: 0 Thanked 0 times in 0 posts
Location: New York, NY
|
Posted: Wed Feb 28, 2007 7:31 am Post subject: GMATPrep - Practice Test #1 - DS - Please Help |
|
|
Any insight would be much appreciated...
7. In the triangle ABC above, what is the length of side BC? 1) Line segment AD has length 6 2) x=36 ( I was not sure how to include the example of the triangle)
9. On the sight seeing tour, the ratio of the number of women to the number of children was 5 to 2. What was the number of men on the sight seeing tour? 1) On the sight seeing tour, the ratio of the number of children to the number of men was 5 to 11. 2) The number of women on the sight seeing tour was less than 30.
|
|
| Back to top |
|
 |
|
|
gabriel Managing Director

Joined: 20 Dec 2006 Posts: 862
Thanks given: 118 Thanked 27 times in 26 posts
Location: India
|
Posted: Sat Mar 03, 2007 8:54 am Post subject: Re: GMATPrep - Practice Test #1 - DS - Please Help |
|
|
| dominate11 wrote: | Any insight would be much appreciated...
7. In the triangle ABC above, what is the length of side BC? 1) Line segment AD has length 6 2) x=36 ( I was not sure how to include the example of the triangle)
9. On the sight seeing tour, the ratio of the number of women to the number of children was 5 to 2. What was the number of men on the sight seeing tour? 1) On the sight seeing tour, the ratio of the number of children to the number of men was 5 to 11. 2) The number of women on the sight seeing tour was less than 30. |
for the first one i dont see a diagram.....
for the second one .... statement 1 along with the information in the question will give u the ratio of men:children:women... which is 22:10:25.... so this statement alone is not sufficient.... statement again does not give u any worthwhile information so this alone is not sufficient either... but take both the statement together and the only possible value of men that wuld satisfy both the given condition is 22 ... so the answer is C
|
|
| Back to top |
|
 |
Stacey Koprince GMAT Instructor

Joined: 27 Dec 2006 Posts: 1248
Thanks given: 0 Thanked 93 times in 83 posts
Location: Bay Area, California GMAT Score: 770
|
Posted: Sun Mar 11, 2007 10:52 pm Post subject: |
|
|
Hi, dominate - if you don't know how to post images, you can also just describe the triangle in text.
_________________ Stacey Koprince
GMAT Instructor
Director of Corporate Development, Northern California
Manhattan GMAT
Contributor to Beat The GMAT!
Learn more about me |
|
| Back to top |
|
 |
Mark Dabral GMAT Instructor
Joined: 26 Oct 2006 Posts: 43
Thanks given: 0 Thanked 0 times in 0 posts
Location: Berkeley, California
|
Posted: Mon Mar 12, 2007 10:01 am Post subject: Here is the image associated with the problem statement |
|
|
Here is the problem from GMATPrep. This problem is also in OG11, and I believe there is a typo in the book. The problem as stated here is correct.
Cheers,
Mark
|
|
| Back to top |
|
 |
snapplesf Just gettin' started!

Joined: 09 Mar 2007 Posts: 14
Thanks given: 0 Thanked 0 times in 0 posts
Location: San Francisco
|
Posted: Tue Mar 13, 2007 10:54 pm Post subject: triangle ABC |
|
|
Hi dominate11 ,
Assuming you figured out the triangle problem. if not,
if you work out the angles, you see that angles BAD=ABD
hence sides AD=BD=BC - hence A is sufficient.
|
|
| Back to top |
|
 |
|
|
hengirl03 Rising GMAT Star
Joined: 05 Aug 2008 Posts: 84
Thanks given: 2 Thanked 4 times in 4 posts
|
Posted: Mon Sep 08, 2008 11:18 pm Post subject: |
|
|
| Would someone please post a detailed explanation to this problem? I'm still confused. Thanks!
|
|
| Back to top |
|
 |
Stacey Koprince GMAT Instructor

Joined: 27 Dec 2006 Posts: 1248
Thanks given: 0 Thanked 93 times in 83 posts
Location: Bay Area, California GMAT Score: 770
|
Posted: Tue Sep 09, 2008 5:59 am Post subject: |
|
|
they ask for a length, so statement 2 is not going to be useful - it gives us an angle only, and you can have a triangle of any size, teeny-tiny to huge, with those angles.
So, ACE.
AD is 6. <BAD is x. <BCD is 2x. <BCD is 2x. They want to know side BC.
<BDC is what's called an exterior angle of triangle BAD. You create this by taking any leg and just extending it out in a straight line. That exterior angle is always equal to the sum of the two opposite interior angles - in this case, angles BAD and ABD. So BAD + ABD = BDC. Fill in what you know. x + ABD = 2x. Solve. ABD = x.
So if ABD = x, it's the same angle as BAD. This means the sides opposite these angles are the same also. We know AD is 6, so BD is also 6.
Now look at the triangle on the right. We also have two identical angles there, so the two opposite sides are the same. One of those sides is BD (which we already know is 6) and the other side is BC, which we want to find. BC is also 6.
So statement 1 is sufficient. Answer is A.
_________________ Stacey Koprince
GMAT Instructor
Director of Corporate Development, Northern California
Manhattan GMAT
Contributor to Beat The GMAT!
Learn more about me |
|
| Back to top |
|
 |
hengirl03 Rising GMAT Star
Joined: 05 Aug 2008 Posts: 84
Thanks given: 2 Thanked 4 times in 4 posts
|
Posted: Tue Sep 09, 2008 10:16 am Post subject: |
|
|
| Thanks Stacey!
|
|
| Back to top |
|
 |
canuckclint Really wants to Beat The GMAT!
Joined: 26 Aug 2008 Posts: 117
Thanks given: 7 Thanked 0 times in 0 posts
Location: Canada Target GMAT Score: 600+
|
Posted: Thu Sep 11, 2008 9:01 pm Post subject: |
|
|
For triangle ABD,
x + angleB + (180-2X) = 180
angleB - x = 0
angleB = x
The right triange is isoceles and you can go from there.
|
|
| Back to top |
|
 |
|