triangle

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 371
Joined: Tue Apr 29, 2008 10:16 am
Thanked: 6 times
Followed by:1 members

triangle

by vaivish » Wed Jun 25, 2008 10:08 am
1) Right triangle PQR is to be constructed in xy-plane so that the right angle is at P and PR is parallel to X-axis. The x and y-coordinates of P, Q, R are to be integers that satisfy the inequalities -4<=x<=5 and 6<=y<=16. How many different triangles with these properties could be constructed?

A) 110
B) 1,100
C) 9,900
D) 10,000
E) 12,100
Source: — Problem Solving |

Master | Next Rank: 500 Posts
Posts: 178
Joined: Wed May 14, 2008 3:51 pm
Thanked: 16 times
Followed by:1 members
GMAT Score:99%+

by egybs » Wed Jun 25, 2008 10:54 am
Heh, i just did this one the other day.

We basically need to pick two points that satisfy x, and two points that satisfy y.

Since there are 10 possible values for x: we do 10*9 and since there are 11 possible values for y we do 11*10.


Multiply those all together, and you get 11*9*10*10 = 99*100 = 9900

C.

If you need more explanation, i'm happy to help.

Legendary Member
Posts: 1153
Joined: Wed Jun 20, 2007 6:21 am
Thanked: 146 times
Followed by:2 members

by parallel_chase » Tue Jul 08, 2008 10:22 am
egybs wrote:Heh, i just did this one the other day.

We basically need to pick two points that satisfy x, and two points that satisfy y.

Since there are 10 possible values for x: we do 10*9 and since there are 11 possible values for y we do 11*10.


Multiply those all together, and you get 11*9*10*10 = 99*100 = 9900

C.

If you need more explanation, i'm happy to help.
Hi I would like to know why did multiply 10*9 and 11*10.

I know that there are 10 values of X and 11 values of Y. But just cant understand the product part.

Thanks