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shipra Rising GMAT Star
Joined: 26 May 2008 Posts: 74
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Location: Dubai
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Posted: Sun Jun 29, 2008 2:52 am Post subject: how many triangles? |
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Right triangle PQR is to be constructed in the xy-plane so that the right angle is at P and PR is parallel to x axis. The x and y coordinated of P,Q & R are to be integers that satisfy the inequalities -4<=x<=5 & 6<=y<=16.
How many different triangles wth these properties are possible?
A. 110
B. 1100
C. 9900
D. 10000
E. 12100 |
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simpdimp Just gettin' started!
Joined: 19 Jan 2008 Posts: 7
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Posted: Mon Jun 30, 2008 6:01 pm Post subject: how many triangles? |
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X coordinate has 10 possible values between -4 and 5
Y coordinate has 11 possible values between 6 and 16
1. Fix P first, P can have 10 values across X axis and 11 across Y axis. So, that's 11*10 = 110
2. Since PR is parallel to X axis, R is on the same line as P. So, R has 9 (10-1) values left along X axis. So far 110*9 = 990
3. Since PQR is a right angle triangle and the right angle is at P, PQ is parallel to Y axis. So, Q has 10 (11-1) values left. So, 990*10 = 9900
The answer is C - 9900 |
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shipra Rising GMAT Star
Joined: 26 May 2008 Posts: 74
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Location: Dubai
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Posted: Mon Jun 30, 2008 11:04 pm Post subject: |
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Thanx a lot...
really helped... |
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rabab Really wants to Beat The GMAT!
Joined: 05 Sep 2008 Posts: 132
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Location: Bangladesh
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Posted: Sat Oct 18, 2008 7:36 am Post subject: Re: how many triangles? |
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| simpdimp wrote: | Since PR is parallel to X axis, R is on the same line as P. So, R has 9 (10-1) values left along X axis.
3. Since PQR is a right angle triangle and the right angle is at P, PQ is parallel to Y axis. So, Q has 10 (11-1) values left. |
Could you pls explain these two lines? Why does R have 9 values and Q have 10 values left? |
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cmoney Just gettin' started!
Joined: 18 Oct 2008 Posts: 4
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Posted: Sun Oct 19, 2008 11:46 am Post subject: |
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I think that the point is that to make a triangle, the the points need to exist on different values. An example would be a triangle where the base points are the same...this creates a line, so it's impossible. Sine R cannot have the same value as P, you have subtract one from the possible locations. (10-1).
I hope that helped. Anyone feel free to correct me if I'm wrong. |
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