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median of r,s and t?

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median of r,s and t?

by pappueshwar » Wed Mar 14, 2012 9:57 am
If r,s and t are different positive integers, what is the median of r,s and t?

1) r+s+t=6
2) rs=2


OA IS D . i feel the answer is C

stmnt : 1 r+ s + t = 6
0+ 1 +5 = 6
1+ 2 + 3= 6 (so median cant be figured)

stmtn : 2 rs = 2, we dont know the value of T.

Together: r+s+t = 6 & rs = 2
1+2+t = 6;
2+1+t = 6
in which ever way it is t= 6-2 = 3

There fore r= 1 s=2 t = 3 median is 2 since for finding the median, the values need to be arranged in ascending or descending order.
C is the answer .

request to let me know where i am going wrong
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by Mike@Magoosh » Wed Mar 14, 2012 1:49 pm
Hi, I'm happy to help with this. :)

The key to this problem is the phrase: " r,s and t are different positive integers." Zero is not a positive number --- zero is the only integer that is neither positive nor negative. Therefore, we can't use zero as one of the numbers.

In Statement #1, the only possibility is {1, 2, 3} in some order, so the median has to be 2

In Statement #2, we know r & s are 1 & 2, in some order, and t is a larger positive integer (since 1 and 2 are the two smallest positive integers). Then, of the three numbers 1, 2, and t, 2 is the median.

Both statements are sufficient. Answer = D

Does this make sense? Let me know if you have any questions.

Mike :)
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by pappueshwar » Wed Mar 14, 2012 6:38 pm
mike thanks...

did nt see the question from that perspective at all... lol :)

thanks once again
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by sam2304 » Wed Mar 14, 2012 11:39 pm
given r,s,t are different +ve integers

1.r+ s + t = 6

So for sum of r,s,t to be 6 we have only one possibility = {1,2,3}

Median = 2. SUFF

2. rs =2.

different positive integers again and we have only 1*2 giving rs = 2. t has to be greater than 2. Be it any number median is again 2. SUFF.

IMO D.
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