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Well here is the ans:
1. xyz < 0 suggests only one of them is -ve.
2. xy <0 suggests x and y lies on two sides of the origin or zero.
So lets draw the number line, and add both the constraints.
|-----------X--------------------------0-----------Y---------------------------------|
Now Z has to be positive. So Z can lie between 0 and Y or beyond Y. But it cannot be beyond Y as XY will be less than XZ. Even if you revert the picture the logic remains the same. So C.
Well here is the ans:
1. xyz < 0 suggests only one of them is -ve.
2. xy <0 suggests x and y lies on two sides of the origin or zero.
So lets draw the number line, and add both the constraints.
|-----------X--------------------------0-----------Y---------------------------------|
Now Z has to be positive. So Z can lie between 0 and Y or beyond Y. But it cannot be beyond Y as XY will be less than XZ. Even if you revert the picture the logic remains the same.
Till this point I agree with devp but ---
The answer should be E. coz in the above figure I can interchange the positions of X and Y
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