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netigen GMAT Destroyer!
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Posted: Sat May 10, 2008 12:09 pm Post subject: PR - Geo Question - Need help |
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Please help with this one
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arorag Really wants to Beat The GMAT!
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Posted: Sat May 10, 2008 1:36 pm Post subject: |
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IMO D
From I
first get AB--then r can be found
from II
again area, r can be found
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netigen GMAT Destroyer!
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Posted: Sat May 10, 2008 1:41 pm Post subject: |
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In (B) I don't understand how can you find r by just knowing the area of the triangle. All we know is:
1. Triangle is isosceles with two sides = r
2. Area of the triangle
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VP_Tatiana GMAT Instructor

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Posted: Sat May 10, 2008 7:09 pm Post subject: |
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Here is how you get r by knowing AD:
Draw a line from A to O. Now we have triangle AOD.
We know AO is r, OD is (r-2), and AD is 6.
You can see we could solve for r using the Pythagorean theorum. Thus, knowing AD is sufficient to solve for r.
Of course, now we could solve for circumference because it is 2pir.
Hope that helped,
Tatiana
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netigen GMAT Destroyer!
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Posted: Sat May 10, 2008 9:23 pm Post subject: |
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Tatiana, that solves for A, how about the option B? In your opinion, is B sufficient to solve for r? If yes, then how?
| VP_Tatiana wrote: | Here is how you get r by knowing AD:
Draw a line from A to O. Now we have triangle AOD.
We know AO is r, OD is (r-2), and AD is 6.
You can see we could solve for r using the Pythagorean theorum. Thus, knowing AD is sufficient to solve for r.
Of course, now we could solve for circumference because it is 2pir.
Hope that helped,
Tatiana |
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amitansu Really wants to Beat The GMAT!
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Posted: Sun May 11, 2008 10:46 am Post subject: |
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From 2:
Area of triangle 1/2 *base*alt=50
here base=alt=radius of traingle
so 1/2r^2=50
r=10
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netigen GMAT Destroyer!
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Posted: Sun May 11, 2008 1:35 pm Post subject: |
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You are assuming the triangle is a right angle triangle. The question doesn't say that its a right angle triangle. This is of course my read on the question and I may be wrong hence need to understand why everyone is interpreting the triangle to be right angled.
| amitansu wrote: | From 2:
Area of triangle 1/2 *base*alt=50
here base=alt=radius of traingle
so 1/2r^2=50
r=10 |
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gabriel Managing Director

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Posted: Sun May 11, 2008 2:37 pm Post subject: |
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| amitansu wrote: | From 2:
Area of triangle 1/2 *base*alt=50
here base=alt=radius of traingle
so 1/2r^2=50
r=10 |
I am confused, how exactly did you reach the conclusion that base = alt=radius. This would be true only if OBC is a isosceles right angle triangle. The question gives no indication of this. I believe the answer should be A, the solution for which is already provided.
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netigen GMAT Destroyer!
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Posted: Sun May 11, 2008 4:08 pm Post subject: |
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BTW the OA by PR for this is D. Explanation assumes the tirangle to the right angled. Anyone know how to give feedback to PR about this error.
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sandeep_chhabra Rising GMAT Star
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Posted: Mon May 12, 2008 1:03 am Post subject: |
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Cant we use the formula for Isosceles Triangle ??
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amitansu Really wants to Beat The GMAT!
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Posted: Mon May 12, 2008 1:56 am Post subject: |
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Yes, there could be a misprint in book.Right angle has to be assumed here.But not necessarily isoseceles triangle !!
Because, for triangle OBC it shows the two sides are nothing but radii.
So the formula can be reduced to 1/2 alt*base=50
=> 1/2*r*r=50
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netigen GMAT Destroyer!
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Posted: Mon May 12, 2008 2:10 am Post subject: |
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Sandeep, the formula you have posted can not be used because one variable in the formula is the base of the triangle and the other is one of the equal sides.
Amit, I also think this is an error on part of PR. This problem is from one of their tests and not from the book.
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