| View previous topic :: View next topic |
| Author |
Message |
maya2008
Just gettin' started!
Joined: 29 Apr 2008
Posts: 12
Thanks given: 7
Thanked 0 times in 0 posts
|
 Posted: Tue May 06, 2008 9:11 pm Post subject: GMAT PREP TEST 1 Q10 - DS |
 |
|
This is a Data sufficiency question. I know I shouldn't solve those but I really hoped someone would help me solve it so I can understand how to deal with these kinds of questions
In a rectangular coordinate system shown above (I didn't attach since it is just a regular coordinate system), does the line k (not shown) intersect quadrant 2?
Statement 1: the slope of the line is -1/6
Statement 2: the y intercept of k is -6
(the answer btw is A)
Thank's a lot...Maya |
|
| Back to top |
|
 |
|
|
Stuart Kovinsky
GMAT Instructor
Joined: 08 Jan 2008
Posts: 838
Thanks given: 0
Thanked 125 times in 116 posts
Location: Toronto
|
| Posted: Wed May 07, 2008 12:00 pm Post subject: Re: GMAT PREP TEST 1 Q10 - DS |
|
|
| maya2008 wrote: | This is a Data sufficiency question. I know I shouldn't solve those but I really hoped someone would help me solve it so I can understand how to deal with these kinds of questions
In a rectangular coordinate system shown above (I didn't attach since it is just a regular coordinate system), does the line k (not shown) intersect quadrant 2?
Statement 1: the slope of the line is -1/6
Statement 2: the y intercept of k is -6
(the answer btw is A)
Thank's a lot...Maya |
First thing to note: quadrant II is the top left quadrant.
So, the question is, does the line pass through the top left section of the co-ordinate system?
Let's start with the easier statement:
(2) the y-int is -6
This tells us that the line passes through (0,-6). We could draw a horizontal line through that point which never touches quadrant 2. We can also draw a diagonal line that does go through quadrant 2. Since the answer is "maybe", (2) is insufficient.
(1) The slope of the line is -(1/6)
You could use trial and error to see that a line with this slope will, eventually, go through sector 2.
Alternatively, you could know this rule:
If a line has a positive slope, it definitely goes through sectors 1 and 3.
If a line has a negative slope, it definitely goes through sectors 2 and 4.
As an aside:
If a line is parallel to the x or y axis, it will go through exactly 2 different sectors.
(Except, of course, for the lines x=0 and y=0, which are the axes.)
If a line is not parallel to the x or y axis it will:
go through exactly 2 sectors if it passes through the origin; or
go through exactly 3 sectors if it does not pass through the origin.
_________________
Stuart Kovinsky, BA LLB
Academic Co-ordinator
Kaplan Test Prep & Admissions
Toronto Office
1-800-KAP-TEST |
|
| Back to top |
|
|
|
maya2008
Just gettin' started!
Joined: 29 Apr 2008
Posts: 12
Thanks given: 7
Thanked 0 times in 0 posts
|
| Posted: Wed May 07, 2008 8:13 pm Post subject: THANX |
|
|
Hey, thanx a million...you really helped me!!!  |
|
| Back to top |
|
|
|
|
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
You cannot attach files in this forum
You cannot download files in this forum
|
|
"GMAT" and other GMAC™ trademarks are registered trademarks of the Graduate Management Admission Council™. The Graduate Management Admission Council™ does not endorse, nor is it affiliated in any way with the owner or any content on this website. The opinions expressed here are solely those of the author or those of the members of this website. Copyright © 2008 BTG Test Prep, LLC. Powered by phpBB © 2001, 2005 phpBB Group.
|
|
