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dferm
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PostPosted: Wed May 07, 2008 10:32 am    Post subject: GMAT PREP ?? (ARITHMETIC MEAN) Reply with quote

What is the average (arithmetic mean) of eleven consecutive integers?

(1) The average of the first nine integers is 7
(2) The average of the last nine integers is 9

Can someone put a little light on this prob?

Thanks.
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rlemaire
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PostPosted: Wed May 07, 2008 11:30 am    Post subject: GMAT Prep?? MEAN Reply with quote

I am not totally sure that I am 100% completely right (you might want to double check) but this is how I view the question you posted below.....

What is the average (arithmetic mean) of eleven consecutive integers?

(1) The average of the first nine integers is 7
(2) The average of the last nine integers is 9

Can someone put a little light on this prob?


To find the Arithmetic Mean of 11 consecutive integers you must view Number 1 to start.

Number 1 tells us that the average of the "first 9" of our consecutive integers must equal 11. I first used integers 1 - 11 but found that when I averaged 1 - 9 I came up to only 6 (Arithmetic Mean). Same thing with 2 - 12 with average of 6. So I tried 3 - 13 and found that the average of 3, 4, 5, 6 , 7, 8, 9, 10, and 11 averaged 7.

I checked this against the second set to see if the average was 9. So, 5, 6, 7, 8, 9, 10, 11, 12, and 13 equal the average of 9 that we are looking for.

There is still one more step and that is to average the 3 - 13. That came out to be 8.

So your answer, as I see it, is 8 and you must use 3 - 13 to get it.

If you want the excel version of what I did then email me and I can upload it.

Hope this helps!!!!!
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Stuart Kovinsky
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PostPosted: Wed May 07, 2008 12:10 pm    Post subject: Re: GMAT PREP ?? (ARITHMETIC MEAN) Reply with quote

dferm wrote:
What is the average (arithmetic mean) of eleven consecutive integers?

(1) The average of the first nine integers is 7
(2) The average of the last nine integers is 9

Can someone put a little light on this prob?

Thanks.


The key is that the integers are consecutive. So, if we can determine any one of the 11 (and know where it falls), we can answer the question.

(1) The average of the first 9 consecutive integers is 7.

We know that avg = sum of terms / # of terms.

So, 7 = sum of terms/9
sum of terms = 63.

Well, there's only going to be one set of 9 consecutive integers that add up to 63. If we can determine the first 9, we can certainly determine the last 2: sufficient.

(2) The average of the last 9 terms is 9.

Exact same reasoning as (1): sufficient.

Both (1) and (2) are sufficient: choose (D).

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