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Source: — Problem Solving |
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by madhavi » Mon Mar 31, 2008 11:54 am
To solve this, we need to know that angle subtended by diameter on any point on a semi-circle is 90. Therefore ABC is a right triangle

AC=2
CB=1

AB= Sqrt(AC^2-CB^2)

AB=Sqrt3

Therfore area of ABC is (1/2)*CB* AB=(sqrt3)/2

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