Q. A box contains identical balls in three different colors - Black, white and blue. There are 8-x blue balls and 2X+5 black balls. If a ball is picked at random from the box, what is the probablity that the ball is either blue or black?
1) X=2
2) There are 3X+39 white balls in the box.
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Weekly Math Quest - Nov26th,2006
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The OA is B.
I will post the solution only if someone is interested.
I will post the solution only if someone is interested.
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[copying what was posted by guardian on Scorechase]
Q. A box contains identical balls in three different colors - Black, white and blue. There are 8-x blue balls and 2X+5 black balls. If a ball is picked at random from the box, what is the probablity that the ball is either blue or black?
1) X=2
2) There are 3X+39 white balls in the box.
1] X=2, clearly insufficient
2] Total balls = 3x+39 + 8-x + 2X+5 = 4x + 52 = 4[x+13]
Probablity of getting either a blue or a black ball = [8-x + 2x + 5] / 4[x+13]
= [x+13]/4[x+13] = 1/4. Suff condition
Choice B.
Q. A box contains identical balls in three different colors - Black, white and blue. There are 8-x blue balls and 2X+5 black balls. If a ball is picked at random from the box, what is the probablity that the ball is either blue or black?
1) X=2
2) There are 3X+39 white balls in the box.
1] X=2, clearly insufficient
2] Total balls = 3x+39 + 8-x + 2X+5 = 4x + 52 = 4[x+13]
Probablity of getting either a blue or a black ball = [8-x + 2x + 5] / 4[x+13]
= [x+13]/4[x+13] = 1/4. Suff condition
Choice B.
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