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by gmatusa2010 » Sun Jan 16, 2011 11:56 pm
At least 100 employees in a certain company have management
experience. If 15 percent of the employees in the company who
have sales experience also have management experience, do
more employees have sales experience than management
experience?


(1) 72 employees in the company have both sales
experience and management experience.
(2) 252 employees in the company have neither sales
experience nor management experience.

How do you evaluate statement 1? I had 15%(S)= 72 where S equal number of with sales experience. OA seems to suggest that its 15%(total)=72 where 72 equal having both. What is the correct interpretation?
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Source: — Data Sufficiency |

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by Anurag@Gurome » Mon Jan 17, 2011 12:21 am
gmatusa2010 wrote:How do you evaluate statement 1? I had 15%(S)= 72 where S equal number of with sales experience. OA seems to suggest that its 15%(total)=72 where 72 equal having both. What is the correct interpretation?
Your interpretation is correct.

The question clearly mentions "15 percent of the employees in the company who have sales experience also have management experience" and statement 1 says, "72 employees in the company have both sales experience and management experience. ".

Therefore, number of employees having both experience = 72
=> 15% of employees with sales experience = 72
=> Number of employees with sales experience = 72/(0.15) = 480
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by [email protected] » Mon Jan 17, 2011 10:28 am
E is the correct answer, isnt it?

At first glance it seems that you can find certain numbers, but the condition "at least" gives us many possible answers, which include both situations: more employees w/sales experience and more employees w/managerial experience.

Therefore both are insufficient.
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by prachich1987 » Mon Jan 17, 2011 10:44 am
Is the OA E?
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by ankur.agrawal » Tue Jan 18, 2011 2:12 am
prachich1987 wrote:Is the OA E?
Wats the OA?
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by aleph777 » Wed Jan 19, 2011 7:01 am
The question is simply asking which number is greater, # of employees with sales experience or # with management experience?

And we are told:

Employees with management experience: 100
Employees with sales experience: N and .15N also have management experience.

STATEMENT 1
72 employees have both sales and management experience. Therefore, 72 = .15N and N = 480.

Thus, there are more employees with Sales experience than with management experience. Sufficient.

STATEMENT 2
252 employees have neither sales nor management experience... This is superfluous info. Therefore, insufficient.

I believe the answer is A.

OA?
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by Anurag@Gurome » Wed Jan 19, 2011 7:35 am
aleph777 wrote:...

Employees with management experience: 100

...
Read the problem statement properly.
There is a "At least" term in the very beginning of the problem.
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by pesfunk » Fri Jan 28, 2011 3:41 am
OA must be E.
Since it says "at least"
Anurag@Gurome wrote:
aleph777 wrote:...

Employees with management experience: 100

...
Read the problem statement properly.
There is a "At least" term in the very beginning of the problem.
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by HSPA » Fri Jan 28, 2011 7:32 am
I am using both options

I have got total emp = 480 from 72/0.15
it was told neither is 252 so P(S)+P(M)+P(MuS) = 480 - 252 = 228

Then from A again P(MuS) = 72 therefore P(S)+p(M) = 156
P(M) is atleast 100 and Here we need to find if P(S) > P(M)

I am getting answer as C :)... what is the wrong I am doing how is it E.
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by GMATGuruNY » Fri Jan 28, 2011 7:34 am
gmatusa2010 wrote:At least 100 employees in a certain company have management
experience. If 15 percent of the employees in the company who
have sales experience also have management experience, do
more employees have sales experience than management
experience?


(1) 72 employees in the company have both sales
experience and management experience.
(2) 252 employees in the company have neither sales
experience nor management experience.
Let:
m = management experience
s = sales experience
b = both management and sales experience
n = neither management nor sales experience
t = total employees

Question: Is s>m?

What we know:
m≥100.
b = .15s

Statement 1: b = 72
.15s = 72
s = 72/(.15) = 480.
If m=100, then s>m
If m=1000, then s<m.
Insufficient.

Statement 2: n = 252
No way to determine whether s>m.
Insufficient.

Statements 1 and 2 together:
Combining the statements, s = 480 and n = 252, but we still don't know the value of m or t.
If m=100, then s>m.
If m=1000, then s<m.
Insufficient.

The correct answer is E.
Last edited by GMATGuruNY on Mon Feb 21, 2011 3:00 pm, edited 3 times in total.
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by chendawg » Mon Feb 21, 2011 2:39 pm
HSPA wrote:I am using both options

I have got total emp = 480 from 72/0.15
it was told neither is 252 so P(S)+P(M)+P(MuS) = 480 - 252 = 228

Then from A again P(MuS) = 72 therefore P(S)+p(M) = 156
P(M) is atleast 100 and Here we need to find if P(S) > P(M)

I am getting answer as C :)... what is the wrong I am doing how is it E.
Can someone elaborate on this? I'm also stuck behind the same thought process. I'm not sure I quite understand the reasoning behind this explanation:
GMATGuruNY wrote:
Statements 1 and 2 together:
t - n = 480 - 252 = 228.
Thus, m+s = 228.
We know that m≥100. Since b = 72, we know that s≥72.
If m=100, then s=128, and m<s.
If m=128, then s=100, and m>s.
Insufficient.

The correct answer is E.
Thanks in advance!
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by GMATGuruNY » Mon Feb 21, 2011 2:58 pm
chendawg wrote:
HSPA wrote:I am using both options

I have got total emp = 480 from 72/0.15
it was told neither is 252 so P(S)+P(M)+P(MuS) = 480 - 252 = 228

Then from A again P(MuS) = 72 therefore P(S)+p(M) = 156
P(M) is atleast 100 and Here we need to find if P(S) > P(M)

I am getting answer as C :)... what is the wrong I am doing how is it E.
Can someone elaborate on this? I'm also stuck behind the same thought process. I'm not sure I quite understand the reasoning behind this explanation.

Thanks in advance!
I've amended my earlier post. Please check whether the amended post helps to clarify the solution.
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by chendawg » Mon Feb 21, 2011 3:19 pm
GMATGuruNY wrote: I've amended my earlier post. Please check whether the amended post helps to clarify the solution.
Thanks a lot! I now realize that I was tripped up on the wording from your write up.
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by thebigkats » Tue Feb 22, 2011 11:32 am
The keywords are as highlighted:

"At least 100 employees in a certain company have management experience. If 15 percent of the employees in the company who have sales experience also have management experience, do more employees have sales experience than management experience? "

So 15% of sales employees also have mgmt. experience. So statement only tells us the total SALES.
Total MGMT is still unknown - stem only tells us that it is >100 and statements don't give any more details on MGMT employees.

Hence E
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by anirudhbhalotia » Tue Apr 26, 2011 3:14 am
GMATGuruNY wrote:
gmatusa2010 wrote:At least 100 employees in a certain company have management
experience. If 15 percent of the employees in the company who
have sales experience also have management experience, do
more employees have sales experience than management
experience?


(1) 72 employees in the company have both sales
experience and management experience.
(2) 252 employees in the company have neither sales
experience nor management experience.
Let:
m = management experience
s = sales experience
b = both management and sales experience
n = neither management nor sales experience
t = total employees

Question: Is s>m?

What we know:
m≥100.
b = .15s

Statement 1: b = 72
.15s = 72
s = 72/(.15) = 480.
If m=100, then s>m
If m=1000, then s<m.
Insufficient.

Statement 2: n = 252
No way to determine whether s>m.
Insufficient.

Statements 1 and 2 together:
Combining the statements, s = 480 and n = 252, but we still don't know the value of m or t.
If m=100, then s>m.
If m=1000, then s<m.
Insufficient.

The correct answer is E.
If 15% is 72, we know total employees(t) as 480. Is it not?
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