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kulksnikhil
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 Posted: Fri Dec 01, 2006 2:50 am Post subject: Median Coffee blend |
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#1 What is the median number of employees assigned per project for the projects at Company Z?
1) 25% of the projects at Company Z have 4 or more employees assigned tto each project
2) 35% of the projects at Company Z have 2 or fewer employees assigned to each project
#2 One Kilogram of a certain coffee blend consists of X kilogram of Type I coffee and y kilogram of Type II coffee. The cost of the blend is C dollars per kilogram, where C=6.5x + 8.5y. Is x<0.8
1) y>0.15
2) C>= 7.3 |
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aim-wsc
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| Posted: Fri Dec 01, 2006 4:53 am Post subject: Re: Median Coffee blend |
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| kulksnikhil wrote: | #1 What is the median number of employees assigned per project for the projects at Company Z?
1) 25% of the projects at Company Z have 4 or more employees assigned tto each project
2) 35% of the projects at Company Z have 2 or fewer employees assigned to each project
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interesting problem.
higher end has 25%
and lower end has 35% of average number of employees.
so there still will be 40% (which comes in the middle of two extremes) of projects which have exact threee employees assigned.
therefore median has to be 3 fit in 35% to 75% of ^ave.-persons-per-project^
ANSWER: both alone are not sufficient but together sufficient.
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aim-wsc
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| Posted: Fri Dec 01, 2006 5:37 am Post subject: Re: Median Coffee blend |
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| kulksnikhil wrote: |
#2 One Kilogram of a certain coffee blend consists of X kilogram of Type I coffee and y kilogram of Type II coffee. The cost of the blend is C dollars per kilogram, where C=6.5x + 8.5y. Is x<0.8
1) y>0.15
2) C>= 7.3 |
EDIT: WRONG INADEQUATE/ WRONG EXPLANATION AHEAD
2#
AGAIN interesting problem.
check ( cautious) while dealing with ^IS^ & yes or no type of problems: they are notorious. 
clearly single inequalities are not sufficient to have a solution.
so if we take both of given conditions simultaneously::::
we can check the formula by putting extreme values.
note that the given data has y is greater than 0.15 while
required problem asks us to check whether x is less than 0.8
(....that clearly tells us the answer as E)
still we should substitute some random value to x and y.
note that x+y=1 kg.
AND therefore refer to the following post.
thankyou.
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Last edited by aim-wsc on Tue Dec 05, 2006 8:19 pm; edited 1 time in total |
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projase
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| Posted: Tue Dec 05, 2006 3:31 pm Post subject: Re: Median Coffee blend |
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I am not sure about your answer...
Consider that C=6.5X+8.5Y>=7.3 and X+Y=1
Then 6.5X+(1-X)8.5>=7.3
1.2>=2X
0.6>=X, meaning that "B" is correct...
Please comment.
| aim-wsc wrote: | | kulksnikhil wrote: |
#2 One Kilogram of a certain coffee blend consists of X kilogram of Type I coffee and y kilogram of Type II coffee. The cost of the blend is C dollars per kilogram, where C=6.5x + 8.5y. Is x<0.8
1) y>0.15
2) C>= 7.3 |
2#
AGAIN interesting problem.
check ( cautious) while dealing with ^IS^ & yes or no type of problems: they are notorious.
clearly single inequalities are not sufficient to have a solution.
so if we take both of given conditions simultaneously::::
we can check the formula by putting extreme values.
note that the given data has y is greater than 0.15 while
required problem asks us to check whether x is less than 0.8
(....that clearly tells us the answer as E)
still we should substitute some random value to x and y.
note that x+y=1 kg.
answer : together both taken insufficient. |
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aim-wsc
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