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Suyog
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 Posted: Mon Nov 26, 2007 9:59 pm Post subject: Coffee beans |
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A grocer bought 24kg of coffee beans at Price X. After a while 1/3 of the stock got spoiled so he sold rest for $200 per kg and made total profit of twice the cost. What must be price of X?
1. $66 2/3
2. $50 1/3
3. $44 4/9
4. $33 1/3
5. $24 1/2 |
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syv11
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| Posted: Mon Nov 26, 2007 10:31 pm Post subject: |
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200*2/3*24-24*x = 2*x*24
400/3-x=2x
x=44.4444, 44 4/9 |
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Suyog
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| Posted: Mon Nov 26, 2007 10:38 pm Post subject: |
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dont know wot im missing...
1/3 * 24 = 8
24 - 8 = 16....thats not spoiled...
16 * 200 = 3200.. cost is 3200 / 2 = 1600
1600 / 24 = 66 2/3..
i think im missing something...but wot??? |
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syv11
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| Posted: Mon Nov 26, 2007 10:50 pm Post subject: |
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You have revenues of 200*16=3200
Your cost depends on the price (x) you bought it
24x
Total profit: 2*24x
3200-24x=2*24x
3200=72x
x=44 4/9 |
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mtr
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| Posted: Thu Nov 29, 2007 11:49 am Post subject: |
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| Suyog wrote: | dont know wot im missing...
1/3 * 24 = 8
24 - 8 = 16....thats not spoiled...
16 * 200 = 3200.. cost is 3200 / 2 = 1600
1600 / 24 = 66 2/3..
i think im missing something...but wot??? |
You divided 3200 by 2 and it should be 3 since the profit was 2 times the cost. So the cost would be 1/3 of the 3200. Hope that helps. |
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