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Jameschan168
- Senior | Next Rank: 100 Posts
- Posts: 37
- Joined: Sun Aug 26, 2007 3:45 pm
- Thanked: 1 times
Hi all,
I think this is a very simple problem but yet I can't seem to get the right answer for some reason. Please let me know if my logic is off.
At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.4. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.3
(B) $0.45
(C) $0.6
(D) $0.75
(E) $0.9
First I set up the three equations
H + C = $3.59
H + F = $4.40
F = 2C
So I solved for the answer and I got C = $0.81.....
I also tried backsolving using the equations above and I couldn't seem to get the right answer, which is E.
Can someone please explain why?
Thanks.
I think this is a very simple problem but yet I can't seem to get the right answer for some reason. Please let me know if my logic is off.
At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.4. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.3
(B) $0.45
(C) $0.6
(D) $0.75
(E) $0.9
First I set up the three equations
H + C = $3.59
H + F = $4.40
F = 2C
So I solved for the answer and I got C = $0.81.....
I also tried backsolving using the equations above and I couldn't seem to get the right answer, which is E.
Can someone please explain why?
Thanks.












