PS ( posted by tutonaranjo)

This topic has expert replies
User avatar
Legendary Member
Posts: 986
Joined: Wed Dec 20, 2006 11:07 am
Location: India
Thanked: 51 times
Followed by:1 members

PS ( posted by tutonaranjo)

by gabriel » Tue Aug 21, 2007 7:46 am
4) Pat, Kate, and Mark charged a total of 162 hours to a project. If Pat charged twice as much time to the project as Kate and 1/3 as much time as Mark, how many more hours did Mark charge to the project than Kate?
a) 18
b) 36
c) 72
d) 90
e) 108
Source: — Problem Solving |

User avatar
Legendary Member
Posts: 986
Joined: Wed Dec 20, 2006 11:07 am
Location: India
Thanked: 51 times
Followed by:1 members

Re: PS ( posted by tutonaranjo)

by gabriel » Tue Aug 21, 2007 8:02 am
gabriel wrote:4) Pat, Kate, and Mark charged a total of 162 hours to a project. If Pat charged twice as much time to the project as Kate and 1/3 as much time as Mark, how many more hours did Mark charge to the project than Kate?
a) 18
b) 36
c) 72
d) 90
e) 108
Ok so let pat have charged 6x hrs of time , then kate would have charged 3x hrs of time and mark would have charged 18x hrs of time ...

So the totla time charged is 6x+3x+18x= 162 .. that is 27x=162 ..so x = 6 ..

So mark charged 18*6 = 108 hrs and kate charged 3*6 = 18 hrs of time ..
that means mark charged 108-18=90 more hrs than kate ...

Senior | Next Rank: 100 Posts
Posts: 42
Joined: Wed Jun 20, 2007 8:45 am
Thanked: 1 times

1/3 as much

by tutonaranjo » Tue Aug 21, 2007 11:09 am
Coulnd't figure out that 1/3 as much time as Mark meant that pat is X and Mark is 3x. Would've thought Pat was x and Mark as 4/3x.
Suppose I will memorize this