Hey guys,
Can anyone help me with this simple question?
5. At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90
Correct answer is (E)
I did solve it this way:
x + y = 3.59
x + 2y = 4.40
but it was wrong.
Thanks in advance for your attention!
Please help
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- gabriel
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let hamburger cost x $..smushkas wrote:Hey guys,
Can anyone help me with this simple question?
5. At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90
Correct answer is (E)
I did solve it this way:
x + y = 3.59
x + 2y = 4.40
but it was wrong.
Thanks in advance for your attention!
let the coleslaw cost y $..
So, the french fries cost 2y $ ..
so the eqn are
x + y = 3.59 and x + 2y = 4.40 ...
.. nothing wrong with the eqn's .. so either the answer choices are wrong or the given numbers are wrong .. i have a feeling that it should be 3.95 $ and not 3.59 $ ..
Thanks a bunch gabriel!
I thought i was totally wrong. Even with the correct answer hamburger price does not make any sense to me.
1) 3.59 - 0.45 = 3.14
2) 4.40 - 0.90 = 3.50
It seems 2 prices were charged for hambugers. There definitely something must be wrong...
Thanks again gabriel for your help!
I thought i was totally wrong. Even with the correct answer hamburger price does not make any sense to me.
1) 3.59 - 0.45 = 3.14
2) 4.40 - 0.90 = 3.50
It seems 2 prices were charged for hambugers. There definitely something must be wrong...
Thanks again gabriel for your help!